Electricity: How Current Works

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SUMMARY

This discussion focuses on the interaction between ammeters and voltmeters in a circuit, particularly when a voltmeter is connected in parallel and allows current to flow through it. The consensus is that the ammeter reading will decrease when current flows through the voltmeter due to the conservation of charge and the effect of the voltmeter's resistance. The equation V=IR is central to understanding these changes, but its application can yield different results depending on the configuration of the circuit and the resistance of the measuring instruments.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Familiarity with Kirchhoff's Laws
  • Basic knowledge of circuit components (ammeter, voltmeter)
  • Concept of resistance in electrical circuits
NEXT STEPS
  • Research Kirchhoff's Current Law and its applications in circuit analysis
  • Explore the impact of meter resistance on circuit performance
  • Learn about ideal vs. non-ideal voltmeters and their effects on measurements
  • Study the principles of series and parallel circuits in depth
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Electrical engineering students, hobbyists building circuits, and anyone interested in understanding the behavior of measuring instruments in electrical systems.

vadevalor
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Refer to my third post :) clearer and the picture in my second post
 
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vadevalor said:
If current flows through a voltmeter in parallel first then it flows back to an ammeter -- any effect on the ammeter and voltmeter reading? (Do they increase or decrease?)
I would assume current measured by the ammeter is the same as when no current flows through the voltmeter, because although current splits before the voltmeter, the current is added up when it leaves the point of split and heads for the ammeter. But i suspect this is not true.

Also, I only rely on using V=IR, but it doesn't work sometimes, so are there other equations to use if this doesn't work?(as in it doesn't prove the increase or decrease)

This is extremely vague. "current ... flows BACK to an ammeter"?

Spend some time producing a circuit diagram and post it here!

Furthermore, if this is part of a HW/Coursework question, please do it in the HW/Coursework forum.

Zz.
 
ImageUploadedByTapatalk1353862200.082398.jpg


Its a simple setup as shown( this is what i thought of so it's not a homework qn)
I put arrows to show a case where current will flow through the voltmeter ( unlike normal case where an ideal voltmeter has an infinite resistance and assumed to have no current through it)
 
You might want to look up Kirchoff's Rule, also. I think you are trying to ask what the ammeter readings will be in that circuit diagram, it can be answered by the said computational method. Intuitively, at the split, the current reading should be lower, this is a direct consequence of the law of conservation of charges.
 
The voltmeter in parallel to the load will indeed decrease the total circuit resistance thus increasing circuit current. Also the Ammeter will have a small resistance in series with the load decreasing the circuit current. To compute the total circuit current you will need to know the resistance of your meters then just compute the total circuit resistance.
 
Comparing a case when no current flow through the voltmeter and when current flows through it -- why would there be an decrease in the reading of the voltmeter from the former to the latter case?

Using V=IR, when I increases due to current flowing through voltmeter but initially there us none, the voltmeter reading should increase.

Using the same equation V=IR, when resistance of the voltmeter has decreased(no longer infinite resistance voltmeter to allow current to flow through it) then considering that factor alone the voltmeter reading should decrease.

Why is the latter case the correct one?- where voltmeter reading decrease (to be less than the emf) from a case of no current through voltmeter to a case where there is current through the voltmeter (the explanation or formula used may be wrong)
And i may have to rephrase my first qn- would the ammeter reading change from a case where no voltmeter is attached and the circuit is in series to a case where a voltmeter is attached as shown above and current PASSES through it?
 

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