Which Cell Reaction Will Form More Products at Equilibrium?

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SUMMARY

The discussion centers on determining which cell reaction will yield more products at equilibrium based on their standard electrode potentials (E°). A positive E° value indicates a spontaneous reaction, while a negative E° value suggests non-spontaneity. The relationship between the equilibrium constant (K) and the E° value is established through the Nernst equation, which states that a higher E° correlates with a larger K, favoring product formation. Thus, the cell reaction with the positive E° will form more products at equilibrium.

PREREQUISITES
  • Understanding of standard electrode potentials (E°)
  • Familiarity with the Nernst equation
  • Knowledge of equilibrium constants (K)
  • Basic concepts of electrochemistry
NEXT STEPS
  • Study the Nernst equation and its applications in electrochemistry
  • Learn how to calculate equilibrium constants from E° values
  • Explore examples of spontaneous vs. non-spontaneous reactions
  • Review the relationship between Gibbs free energy and cell potential
USEFUL FOR

Chemistry students, particularly those preparing for exams in electrochemistry, and educators seeking to clarify concepts related to cell reactions and equilibrium.

Etienne
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Homework Statement


The E° value of one cell reaction is positive and that of another cell reaction is negative. Which cell reaction will proceed toward the formation of more products at equilibrium?
*Problem 19.20, Chemistry: Chang, Raymond. 10th ed.

Homework Equations


E° cell = E° cathode - E° anode

I have an exam on Friday and I can't really see how which one would form more products in equilibrium, and that worries me. Please help. :(
 
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Do you know any equations that relate the equilibrium constant (K) to the E° value of your reaction?
 

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