How Do You Write the Balanced Reaction Equation for an Iron-Nickel Cell?

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SUMMARY

The balanced reaction equation for an iron-nickel cell involves the oxidation of iron and the reduction of nickel ions. The standard cell potential (∆E⁰) is calculated as 0.66V. At equilibrium, the cell potential (∆E) equals 0V, indicating that the reaction quotient (Q) is equal to the equilibrium constant (Ke). To determine the value of n, which represents the number of moles of electrons transferred, one must write the balanced half-reaction equations for both the oxidation and reduction processes.

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  • Understanding of electrochemical cells and half-reactions
  • Knowledge of standard electrode potentials
  • Familiarity with the Nernst equation
  • Basic concepts of chemical equilibrium
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  • Study the Nernst equation in detail for various electrochemical cells
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  • Investigate the calculation of equilibrium constants (Ke) from reaction quotients (Q)
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Chemistry students, electrochemists, and anyone studying redox reactions and electrochemical cells will benefit from this discussion.

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Homework Statement


An iron-nickel cell uses a salt bridge to join a half-cell containing a strip of iron in a 1mol/L solution of Fe2+ to a half cell which contains a strip of nickel in a 1mol/L Ni2+ solution. Calculate Ke for the reaction.


Homework Equations



∆E = ∆E⁰ - .0592V/n log Q

The Attempt at a Solution



so using ∆E⁰= ∆E⁰r (cathode) - ∆E⁰r (anode), I know that ∆E⁰= .66V, and I also know that at equilibrium ther is 0V, so ∆E =0. I know that Q is = to Ke, so i need to solve for Q. Problem is I don't know how to find the value of n (the amount, in moles, of electrons transferred according to the cell reaction)
 
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Have you tried the simplest approach - write balanced reaction equation?
 

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