SUMMARY
The electrolysis of molten sodium chloride (NaCl) produces sodium (Na) and chlorine gas (Cl2), while the electrolysis of an aqueous NaCl solution results in sodium hydroxide (NaOH) and chlorine gas (Cl2). This difference is due to the reduction potential of hydrogen ions (H+) being more favorable than that of sodium ions (Na+). The relevant half-reactions are 2H+ + 2e- → H2 (E° = 0 V) and 2Cl- → Cl2 + 2e- (E° = -1.358 V). Consequently, during electrolysis in water, H+ is reduced to form hydrogen gas, leaving hydroxide ions (OH-) in solution.
PREREQUISITES
- Understanding of electrolysis principles
- Knowledge of reduction potentials in electrochemistry
- Familiarity with half-reaction notation
- Basic concepts of ionic compounds and their behavior in molten and aqueous states
NEXT STEPS
- Study the electrolysis of other ionic compounds, such as potassium chloride (KCl)
- Learn about the Nernst equation and its application in electrochemical cells
- Research the industrial applications of sodium hydroxide production via electrolysis
- Explore the effects of concentration on electrolysis outcomes in different solvents
USEFUL FOR
Chemistry students, electrochemists, and professionals in chemical manufacturing who are interested in the principles and applications of electrolysis in producing chemical compounds.