Electrolysis of NaCl: Na+ + Cl- to NaOH + Cl2

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SUMMARY

The electrolysis of molten sodium chloride (NaCl) produces sodium (Na) and chlorine gas (Cl2), while the electrolysis of an aqueous NaCl solution results in sodium hydroxide (NaOH) and chlorine gas (Cl2). This difference is due to the reduction potential of hydrogen ions (H+) being more favorable than that of sodium ions (Na+). The relevant half-reactions are 2H+ + 2e- → H2 (E° = 0 V) and 2Cl- → Cl2 + 2e- (E° = -1.358 V). Consequently, during electrolysis in water, H+ is reduced to form hydrogen gas, leaving hydroxide ions (OH-) in solution.

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Homework Statement


Why does electrolysis of molten NaCl yield sodium and chlorine, while electrolysis of a solution of NaCl in water yields sodium hydroxide and chlorine.

Homework Equations



The Attempt at a Solution


Is it because H+ is more readily reduced than Na+?

2H+ + 2e --> H2 Eo= 0
2Cl- --> Cl2 + 2e Eo=-1.358

Thus, 2H+ + 2Cl- --> Cl2 H2 Eorxn=-1.358 V

And so 2H+ --> H2, leaving OH- behind in place of Cl-
 
Last edited:
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Any ideas? You see, that template that you should use is not a joke, but a tool to force you follow forum rules.

--
methods
 
Is it because H+ is more readily reduced than Na+?

2H+ + 2e --> H2 Eo= 0
2Cl- --> Cl2 + 2e Eo=-1.358

Thus, 2H+ + 2Cl- --> Cl2 H2 Eorxn=-1.358 V

And so 2H+ --> H2, leaving OH- behind in place of Cl-
 
Last edited:
plexus0208 said:
Is it because H+ is more readily reduced than Na+?

Yes. Note that further discussion is irrelevant, as you should compare reduction potentials of H+ and Na+, chlorine reaction doesn't change.

--
methods
 

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