Electrolytic reduction of iron ore - Stoichiometry

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SUMMARY

The discussion focuses on calculating the maximum mass of aluminum that can be produced from 408 tonnes of alumina through electrolysis. The relevant equations include the cathodic reaction of Al3+ ions and the anodic reaction of O2- ions. Participants emphasize the importance of determining the moles of aluminum oxide and the stoichiometric conversion to aluminum. Additionally, the discussion touches on formatting chemical equations using LaTeX and HTML tags for clarity.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Familiarity with electrolysis processes
  • Knowledge of LaTeX for chemical notation
  • Basic principles of metallurgy
NEXT STEPS
  • Calculate moles of aluminum oxide from 408 tonnes of alumina
  • Determine the stoichiometric ratio of aluminum produced per mole of aluminum oxide
  • Convert moles of aluminum to mass using molar mass calculations
  • Explore LaTeX formatting for chemical equations in academic writing
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Chemistry students, metallurgists, and educators looking to enhance their understanding of electrolysis and stoichiometric calculations in aluminum production.

ThetaPi
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Homework Statement



Calculate the maximum mass of aluminum that can be made from 408 tonnes of alumina, assuming that aluminum is produced by electrolysis.

Homework Equations



At the cathode: Al^{3+} (l) + 3e^{-} \Rightarrow Al (l).

At the anode: O^{2-} (l) \Rightarrow O_2 (g) + 4e^{-}. Is the oxide ion from aluminum oxide in liquid or gaseous state?

The Attempt at a Solution



Is there any limiting reagent of sorts? I have never done any stoichiometric calculations on metallurgy.

Postscript. How do we input chemistry using LaTeX? (Especially the chemical equations and symbols, e.g. how to make Al not italicized.)
 
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ThetaPi said:

Homework Statement



Calculate the maximum mass of aluminum that can be made from 408 tonnes of alumina, assuming that aluminum is produced by electrolysis.

Homework Equations



At the cathode: Al^{3+} (l) + 3e^{-} \Rightarrow Al (l).

At the anode: O^{2-} (l) \Rightarrow O_2 (g) + 4e^{-}. Is the oxide ion from aluminum oxide in liquid or gaseous state?

The Attempt at a Solution



Is there any limiting reagent of sorts? I have never done any stoichiometric calculations on metallurgy.

Postscript. How do we input chemistry using LaTeX? (Especially the chemical equations and symbols, e.g. how to make Al not italicized.)
Regarding formatting, LaTeX posts on PF are automatically in math mode, which means that all letters are italicized (which is the conventional way to typeset mathematical variables). However, the following LaTeX output (without the spaces in the tex tags) will generate the result given below it:

[ tex ] \textrm{Al}^{3+}_{(\textrm{l})} +3e^{-} \longrightarrow \textrm{Al}_{(\textrm{l})} [ /tex ]

\textrm{Al}^{3+}_{(\textrm{l})} +3e^{-} \longrightarrow \textrm{Al}_{(\textrm{l})}

where the \textrm{} environment takes us out of math mode and into normal text mode using the roman font.
 
Regarding the problem, it's been a while since I've done chemistry, but isn't it merely a matter of:

1. Figuring out how many moles of aluminum oxide correspond to 408 tonnes of it.
2. Figuring out how many moles of Al are produced per mole of aluminum oxide
3. Converting that many moles of Al into a mass, assuming all of it is converted?

Edit, and here's a non LaTeX alternative which might or might not be easier for chemistry (your choice). Use the sup and sub tags for superscripts and subscripts respectively

This input, without spaces in the tags, produces the output below it:

Al[ sub ](l)[ /sub ][ sup ]3+[ /sup ] + 3e[ sup ]-[ /sup ] → Al [ sub ] (l) [ /sub ]​

Al(l)3+ + 3e- → Al(l)
 

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