Electromagnetic waves radiating away from a transmitting tower

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DottZakapa
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Homework Statement
A radio station on the surface of the earth radiates a sinusoidal wave with an average total power of 50 kw. Assuming that the transmitter radiates equally in all the directions above the ground, at a distance of 100 km from the antenna (ε0 = 8.85 10-12 C2N-1m-2)
Relevant Equations
electromagnetic waves
Homework Statement: A radio station on the surface of the Earth radiates a sinusoidal wave with an average total power of 50 kw. Assuming that the transmitter radiates equally in all the directions above the ground, at a distance of 100 km from the antenna (ε0 = 8.85 10-12 C2N-1m-2)
Homework Equations: electromagnetic waves

I divide the power by the half sphere
50000/(4πr2/2)
In such way i get the intensity per surface unity right?
which is also equal to
I=cε0E2
Now, from this equation i solve for E if i want to get Emax right ?
In case i need Bmax i divide Emax by c
Is there any error ? because can't get the right result
 
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DottZakapa said:
I divide the power by the half sphere
50000m/((4πr2)/2)
In such way i get the intensity per surface unity right?
That's the right approach (but I don't know what the "m" is for in your expression).
DottZakapa said:
which is also equal to
I=cε0E2
Where did you get that equation?
 
Doc Al said:
That's the right approach (but I don't know what the "m" is for in your expression).

Where did you get that equation?
that equation comes from:

Screen Shot 2019-08-25 at 20.26.43.png
total energy density

Screen Shot 2019-08-25 at 20.27.07.png
relation between E and B

Screen Shot 2019-08-25 at 20.27.15.png


Screen Shot 2019-08-25 at 20.28.10.png
energy flow per unit area per unit time

But i realized that this leads to instantaneous intensity, in order to get the average intensity , S must be divided by 2.
Doing so you get the average intensity,

Screen Shot 2019-08-25 at 20.39.21.png


which leads to the correct result.
Thanks 👍 very kind.
 
DottZakapa said:
But i realized that this leads to instantaneous intensity, in order to get the average intensity , S must be divided by 2.
Exactly. Good work!
 
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