Electromagnetism, current in coil

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1. A coil of 25 turns of wire is suspended by a thread. When a current flows through the coil, the tension in the thread is reduced by 4.0 x 10-2 N. What are the magnitude and direction of the current? {magnitude of current; direction of current}

a) 4.1 A; clockwise
b) 0.16 A; clockwise
c) 0.16 A; counter-clockwise
d) 4.1 A; counter-clockwise



Homework Equations



F=IlB
B= [itex]\frac{\mu NI}{l}[/itex]

The Attempt at a Solution



B=[itex]\mu[/itex]NI/l
F= IlB = Il([itex]\mu[/itex]NI/l) = I2[itex]\mu[/itex]N
I = [itex]\sqrt{ \frac{F}{\mu N} }[/itex]

so I = √4.0x10-2 / 4∏x10-7 x25 = 35.48A

My answer doesn't match with any of theirs.

Also, how would I find the direction of current? I don't know the direction of B (magnetic field).

Any help would be greatly appreciated.
 
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Show your reasoning - why would you expect that a current through the wire would decrease the tension in the thread?
 
Just posting to get on the thread. Seems like there's a lot of info missing. Seems like this problem gives a whole new meaning to "pulling yourself up by the bootstraps"! :smile:
 
Simon Bridge said:
Show your reasoning - why would you expect that a current through the wire would decrease the tension in the thread?

Is there uniform circular motion involved?
 
Is there uniform circular motion involved?
You are the one with the whole problem statement in front of you, you tell me: is their uniform circular motion involved?