- #1

Kweh-chan

- 3

- 0

## Homework Statement

Consider an infinitely long and thin line of charge, with density 8nC/m. Calculate the electric potential difference ((phi)1-2) between two points in air at radial disances 1mm and 3mm.

## Homework Equations

I am assuming:

Phi(r) = λ/2(pi)ε0 * ln(rR/r) where rR is a reference point

## The Attempt at a Solution

Our lecturer told us that we did not have to derive electric potential - just use what we had discussed in the notes, which, as far I can tell, is the above.

As far as I can see, this is just plugging in 8x10^-9 c for λ, 3x10^-3m for rR, and 1x10^-3m for r.

The problem: this is a 20 point question! One fifth of the assignment's points.

I feel like there is something to this that I am missing, but, despite having poured through our notes and researched on the internet (and even found a worked problem that is similar), I cannot find anything else to do other than plug in for λ, rR, and r.

If I'm wrong and there's a lot more I have to do, could someone please help point me in the right direction?

## Homework Statement

The potential at position

**r**due to a point charge

*q*at position

**r'**is

phi(r) = q/4piε0 * 1/|

**r**-

**r'**|

a.) Calculate grad phi and hence the electric field

**E**.

b.) What is the force experienced by a charge

*q1*at position

**r**?

c.) What is the potential energy of the charge at

*q1*?

## Homework Equations

Given above; however, also worth knowing is

E = -grad phi

U = q2 * phi

## The Attempt at a Solution

This is like the above question, where, in my mind at least, the points allocated don't seem to match up with the amount of work to be done.

Part a I have no problems with. I thought of r in terms of x,y, and z (again, according to our lecturer's advice), and then I used partial derivative with respect to x, then stated that, according to symmetry, y and z worked out to be the same, giving an answer of

grad phi = q/4piε0 *

**r'**-

**r**/|

**r**-

**r'**|^3

and since E = -grad phi, this reversed the top value (r'-r) to give

E = = q/4piε0 *

**r**-

**r'**/|

**r**-

**r'**|^3.

That felt like a solid 10 points worth of work.

To do part b, it seems that all I have to do is multiply another q into the equation, and multiply that by -1 (since the charge is going from q1 (which I assume is equivalent to "q2") to q (which I assume is equivalent to "q1")). This feels more like 2 or 3 points worth of work.

Then for part c, I have done a negative integral of what I calculated for F, with respect to r. This gives me

U = q*q1/4piε0 * 1/|r-r'|

Not only does this answer not seem correct, but it also doesn't feel like 10 points worth of work.

Again, if someone could help me see where I went wrong, and point me in the direction of whatever I'm missing, I would be very grateful.

Thanks!