Electron delocalization in Benzophenone

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SUMMARY

In benzophenone, not all atoms except hydrogens participate in electron delocalization due to the nature of the carbonyl group. While the conjugated pi bonds in the two benzene rings contribute to delocalization, the oxygen atom in the carbonyl group does not participate because it tends to attract electrons, creating a dipole moment. This results in a partial negative charge on the oxygen and a partial positive charge on the carbon, preventing full delocalization across the molecule.

PREREQUISITES
  • Understanding of conjugated pi systems
  • Knowledge of sigma and pi bonds
  • Familiarity with dipole moments and electronegativity
  • Basic concepts of molecular orbital theory
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  • Study the concept of resonance structures in organic molecules
  • Learn about the effects of electronegativity on molecular stability
  • Explore molecular orbital theory as it applies to conjugated systems
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Chemistry students, organic chemists, and anyone studying molecular structures and electron delocalization in aromatic compounds.

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Homework Statement


Are all the atoms except the hydrogens involved in electron delocalization in benzophenone?


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The Attempt at a Solution



Yes as the double bonds are in conjugation. But we were told that the answer is no. Can anybody explain why this so?
 
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Distinguish between the pi and sigma electrons. I am not certain whether the pi bond on the carbonyl group participates with the benzenes , at the moment I am not able to envision it doing so.
 
i would think that because of the stability of the two benzene rings they are very well delocalized, however oxygen from the carbonyl would give a partial negative charge itself and the carbon a partial positive, leaving a dipole moment towards oxygen. All carbons in the benzene ring DO contribute to the delocalization in the conjugated pi bonds, but the oxygen does not because its tendency is to want to take the electrons from carbon. if that makes sense.
 

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