Electron held up against force of gravity

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IbrahimZCL
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Homework Statement



an electron is held up against the force of gravity by the attraction of a fixed proton some distance above it. How far above the electron is the proton?

Homework Equations



F= ((K)(Q1)(Q2))/R^2

Qe = 1.6x10^-19

The Attempt at a Solution



Using the formula for Coulombs Law I used the K constant of 9x10^9 and Qe for Q1 and Q2. This is all divided by R^2 (I'm solving for R). The problem is I don't know if there is a gravitational constant for Force or what I'm missing. What's the next step?
 
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