# Elevation of Sun above water surface

1. Feb 8, 2014

### Agarb

1. The problem statement, all variables and given/known data

An underwater scuba diver sees the Sun at an apparent angle of 44.5° above the horizontal. What is the actual elevation angle of the Sun above the horizontal? (Use 1.333 for the index of refraction of water.)

2. Relevant equations

n1sin(Θ1) = n2sin(Θ2)

3. The attempt at a solution

I've been doing:

1.333*sin(43) = .9091

sin-1(.9091)= 65.38

90-65.38 = 24.62 degrees

Where am I going wrong?? The answer is 12.9 degrees, but every time I try to do it, I get 24.62 degrees.

2. Feb 8, 2014

### Staff: Mentor

Where does the 43 come from?

I get 18 degrees.

3. Feb 9, 2014

### Agarb

What are the steps you're taking?

4. Feb 9, 2014

90-44.5 = ?

5. Feb 9, 2014

### Staff: Mentor

The same steps as you, just with the right numbers. See the open question in post 2 and 4.

6. Feb 10, 2014

### Agarb

I don't understand where you see a 43?

7. Feb 10, 2014

### Staff: Mentor

I highlighted it.

8. Feb 10, 2014

### Agarb

Shoot sorry, I copied it over and forgot to change it. It should be 44.5

But I still don't get the correct answer

9. Feb 10, 2014

### haruspex

No, not that either: 44.5° above the horizontal

10. Feb 19, 2014

### Agarb

What does that mean?? I tried 90-44.5 and 180-44.5 but it doesn't work. Am I going crazy??

11. Feb 19, 2014

### haruspex

That should do it. Please post you working.