1. The problem statement, all variables and given/known data A small light is 22.0 cm below the surface of a liquid of refractive index 1.50. Viewed from above, the light appears to illuminate a circle on the surface of the water. What is the diameter of the circle? cm 2. Relevant equations Snell's Law n1sin(θ)1 = n2sin(θ)2 3. The attempt at a solution Based on Snell's law: 1.6 x 1 = 1 x sinθ, if I can find the angle of refraction, then maybe I can find the diameter of the circle with trigonometry? I can't really see a way through this one - I'm thinking that I want to find the 'radius' of the circle, and from there, find the diameter. Maybe the distance that the light is used below the circle can be then used as a side for trigonometry to find the radius?