Elevator Problem: What is the Normal Force Acting on a Person?

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SUMMARY

The normal force acting on a 74.0 kg person inside an elevator accelerating upward at 1.43 m/s² is calculated using the formula N = m(a + g), where g is the acceleration due to gravity (9.8 m/s²). The total normal force is determined to be 831.02 N. This calculation incorporates both the gravitational force and the additional force due to the elevator's acceleration. It is essential to understand that the normal force is not simply equal to the gravitational force but rather the net force acting on the person in the elevator.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of gravitational force calculation (mg)
  • Familiarity with the concept of normal force in physics
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of normal force in non-inertial reference frames
  • Learn about free-body diagrams and their application in mechanics
  • Explore the effects of varying acceleration on normal force in different scenarios
  • Investigate the relationship between normal force and frictional force
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Physics students, educators, and anyone interested in understanding forces in motion, particularly in elevator systems and dynamics.

TheFlemster
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Homework Statement


A 74.0 kg person is standing inside an elevator. The elevator is moving from the 3rd floor to the 21st floor. As the elevator passes the 4th floor it is moving at 2.30 m/s and is increasing speed at a rate of 1.43 m/s2 . At this moment, what is the normal force that acts on the person?

Homework Equations


normal Force, N = m(a+g)
F = ma

The Attempt at a Solution


The attempt at solution is on the attached image. Am I working it correct or should I have used F=ma?
 

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Remember that the F in F=ma denotes the vector sum of all external forces. There are two external forces on the person.
 
I believe your answer is correct. The formula N = m(a+g) looks like something pulled out of thin air. If you want to show that you understand the physics, start with Fnet = ma. :oldsmile:
 
So then I ignore the acceleration of 1.43 m/s^2? I am still confused as to which way I am supposed to work it
 
TheFlemster said:
So then I ignore the acceleration of 1.43 m/s^2? I am still confused as to which way I am supposed to work it
No, don't ignore it. The acceleration of 1.43 m/s2 is the "a" in F = ma. Start with F = ma and fill in the left-hand side as suggested by @jbriggs444.
 
F=mg + ma
F=(74)(9.8) + (74)(1.43)
F=831.02 N
Wouldn't this be the total force acting on the person?
 
No, ma does not represent a force acting on the person. mg + ma does not represent the total force acting on the person.

What are the two actual forces acting on the person?
 
The normal force and the force due to gravity?
 
TheFlemster said:
The normal force and the force due to gravity?
Yes, good. So, how would you combine these two forces to represent (symbolically) the net force acting on the person?

Your answer can then be used for the left side of Fnet = ma.
 
  • #10
N=mg
 

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  • #11
Your diagram of the forces looks good. But there is no reason why the two forces should equal one another. The net force is the combination of the two forces. How would you combine the normal force N (which is upward) with the gravitational force mg (which is downward) to get an expression for the total force Fnet?
 
  • #12
Fnet=N-mg
Fnet=ma
combining the two, ma=N-mg
then, N=ma + mg
N=(74)(1.43) + (74)(9.8)
N=831.02
 
  • #13
Yes, good. Include units.
 
  • #14
so the correct answer would be a 831.02 N normal force acting on the person?
 
  • #15
Yes. Do you have the correct number of significant figures in you answer?
 

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