Emf in coil rotating inside magnetic field

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SUMMARY

The discussion centers on the induced electromotive force (emf) in a coil rotating within a magnetic field. The key formula referenced is $$\varepsilon=-\frac{d\phi}{dt}$$, where the magnetic flux $$\Phi$$ is defined as $$\Phi=(\mathbf B\cdot\mathbf{\hat n})~A$$. The participants conclude that the induced emf is zero because the magnetic field component normal to the area of the coil does not change as the coil rotates, resulting in no change in magnetic flux over time.

PREREQUISITES
  • Understanding of electromagnetic induction principles
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  • Knowledge of the relationship between emf and magnetic flux change
  • Basic understanding of rotational motion in physics
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songoku
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Homework Statement
Please see below
Relevant Equations
emf = - dφ / dt
1712279767802.png


My answer is (B) but the answer key is (A).

My working:
$$\varepsilon=-\frac{d\phi}{dt}$$
$$=-AB\frac{cos\omega t}{dt}$$
$$=AB\omega \sin \omega t$$

Why the answer is zero? I thought the flux will be zero, not the emf.

Thanks
 
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songoku said:
Why the answer is zero? I thought the flux will be zero, not the emf.
How much of the magnetic field ##B## is normal to the area ##A##?
 
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Look at the deifiniton for flux. ##\Phi=(\mathbf B\cdot\mathbf{\hat n})~A## where ##\mathbf {\hat n}## is perpendicular to the plane of the coil. As you say, the flux is zero. You get an induced emf if the flux changes with time. Does it?
 
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renormalize said:
How much of the magnetic field ##B## is normal to the area ##A##?
kuruman said:
Look at the deifiniton for flux. ##\Phi=(\mathbf B\cdot\mathbf{\hat n})~A## where ##\mathbf {\hat n}## is perpendicular to the plane of the coil. As you say, the flux is zero. You get an induced emf if the flux changes with time. Does it?
Ah I see. Seeing the rotation of the coil with respect to magnetic field, there won't be any B passing through the coil so the rate of change of magnetic flux is zero.

Thank you very much renormalize and kuruman
 

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