Available Energy of Stationary & Moving Particles

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Discussion Overview

The discussion centers around the formula for available energy of stationary and moving particles, specifically addressing the units of measurement for mass within the context of this formula. The scope includes conceptual clarification and technical reasoning related to units in different measurement systems.

Discussion Character

  • Conceptual clarification, Technical explanation

Main Points Raised

  • One participant presents a formula for available energy and inquires about the unit of measurement for mass.
  • Another participant suggests that if the speed of light (C) is in m/s and energy (E) is in Joules, then mass would be in kilograms (Kg).
  • A third participant questions the reasoning behind the unit choice, expressing uncertainty about the explanation.
  • A later reply attempts to clarify by referencing the definition of the Joule and explaining how different measurement systems (CGS and imperial) would require different mass units for consistency in energy calculations.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the reasoning behind the unit of measurement for mass, as one participant expresses confusion about the explanation provided.

Contextual Notes

The discussion highlights the dependence on the definitions of energy units and the implications of using different measurement systems, but does not resolve the underlying uncertainties regarding unit conversions.

Who May Find This Useful

Individuals interested in the relationships between energy, mass, and measurement systems in physics may find this discussion relevant.

HarryDaniels
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In the formula of available energy of a stationary particle and a moving particle:

Ea=(square route of)2MtC^2+(MtC^2)^2+(MkC^2)^2

where:
Mt= mass of stationary particle
Mk= kinetic energy of stationary particle
C= speed of light (299,792,458)

Can someone tell me what the unit of measurement for the mass of the particle.
Thanks
 
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Assuming that C is in m/s and E is in Joules = it would be Kg
 
This may sound like a stupid question, but why?
 
Pretty much from the definition of the Joule

In CGS you would need mass in g, speed in cm/s and you would get an answer in Ergs.
But in imperial units you would need a conversion factor for lbs, ft/s and BTU/HP - it's just that for metric systems the definition of the unit of energy makes the factor =1
 

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