Energy changes of a stretched string

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Homework Help Overview

The discussion revolves around the energy changes in a stretched string, particularly focusing on the relationship between stretching, velocity, and height. Participants are examining the implications of Hooke's Law and the conservation of energy in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand how a reduction in force due to extension affects velocity and height. Questions are raised about the relationship between spring force and gravitational force at different points, particularly below a reference point R.

Discussion Status

The discussion is active, with participants exploring various interpretations of the forces involved and their effects on motion. Some guidance has been offered regarding the relationship between acceleration and velocity, but questions remain about the underlying principles and the reasoning behind height changes.

Contextual Notes

There are references to a mark scheme that suggests height increases, which prompts further inquiry into the reasoning behind this assertion. Participants are also navigating assumptions about the behavior of forces in the system.

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Homework Statement


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This is the answer :

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For part d) of this question, I don't understand "stretching/extension reduces and velocity increases/height increases" .

Homework Equations


Hooke's Law: F=kx

The Attempt at a Solution


Ok, so if extension is reduce, then force reduces too. Then how does a decrease in force causes the velocity and height to increase? Does it have something to do with the principle of conservation of energy, where a gain in kinetic energy equals to a lose in gravitational potential energy?
 
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At a point lower than R , how does spring force compare to force of gravity ?
 
Qwertywerty said:
At a point lower than R , how does spring force compare to force of gravity ?

Spring force is more than the force of gravity .
 
Janiceleong26 said:
Spring force is more than the force of gravity .
So as long as mass is below R , acceleration is ( +ve or -ve ) ? And therefore velocity will always what ?
 
Qwertywerty said:
So as long as mass is below R , acceleration is ( +ve or -ve ) ? And therefore velocity will always what ?

Positive..? I'm not sure.. Therefore, velocity will increase?
 
Janiceleong26 said:
Positive..? I'm not sure.. Therefore, velocity will increase?
Yes . ( kx - mg = ma ) , kx > mg .

Now , a = dv/dt . As a is always positive till before R , dv is always +ve , and hence velocity will increase till R .

Hope this helps .
 
Qwertywerty said:
Yes . ( kx - mg = ma ) , kx > mg .

Now , a = dv/dt . As a is always positive till before R , dv is always +ve , and hence velocity will increase till R .

Hope this helps .

But how do you know that a is always +ve till before R? And why height increases? Does it got to do with 1/2 mv^2=mgh (gain in kinetic energy=lost in gravitational potential energy) ? And thanks by the way. :)
 
Janiceleong26 said:
But how do you know that the a is always +ve till before R?
I thought we agreed that -
Qwertywerty said:
( kx - mg = ma ) , kx > mg .
Janiceleong26 said:
And why height increases?
It rises because acceleration is upwards . And that's pretty much the only reason .
 
Qwertywerty said:
I thought we agreed that -It rises because acceleration is upwards . And that's pretty much the only reason .

Yeah, I agreed to that one. But the mark scheme also states that the height increases as well. Why?
 
  • #10
Janiceleong26 said:
Yeah, I agreed to that one. But the mark scheme also states that the height increases as well. Why?
Qwertywerty said:
It rises because acceleration is upwards . And that's pretty much the only reason .
 
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  • #11
OK thanks
 

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