Energy Levels and Wave Functions of Identical Particle Systems

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SUMMARY

The discussion focuses on calculating the energy levels and wave functions for identical particle systems in a harmonic potential. The ground state energy level is determined using the formula (n + 1/2)ħω, yielding E0 = (1/2)ħω for n = 0, and the first excited state energy is E1 = (3/2)ħω for n = 1. The wave functions are explicitly defined as φ0(x') = 1/sqrt(sqrt(π)R) e−x'²/(2R²) for the ground state and φ1(x') = sqrt(2/sqrt(π)R³)x'e−x'²/(2R²) for the first excited state, where R = sqrt(ħ/(mω)). Participants are reminded to post homework questions in the appropriate forum to avoid warnings.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly harmonic oscillators.
  • Familiarity with the Schrödinger equation and wave functions.
  • Knowledge of Clebsch-Gordan coefficients for identical particle systems.
  • Basic proficiency in mathematical concepts involving exponential functions and square roots.
NEXT STEPS
  • Study the derivation of energy levels in quantum harmonic oscillators.
  • Explore the properties and applications of wave functions in quantum mechanics.
  • Learn about the role of Clebsch-Gordan coefficients in quantum mechanics.
  • Investigate the implications of identical particle statistics in quantum systems.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those studying identical particle systems and harmonic potentials, as well as educators preparing homework assignments in this field.

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TL;DR
Consider a system of two noninteracting spin 1/2 identical particles moving in a common
external harmonic oscillator potential.
a) Find the energy levels of the ground state and the first excited state.
b) Find the wave functions (in the coordinate representation) of the ground state and the first excited state.
Hints: For a particle of mass m in a harmonic potential of angular frequency ω, the energy of the particle in the n = 0, 1, 2,... state is given by (n + 1/2)ħω; the wave functions for the ground state (n = 0) φ0(x') and the first excited state (n = 1) φ1(x') are given by φ0(x') = 1/sqrt(sqrt(π)R) e−x'2/(2R²) , φ1(x') = sqrt(2/sqrt(π)R³)x'e−x'2/(2R²), with R = sqrt(ħ/(mω)). You can use a table of Clebsch-Gordan coefficients.
 
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