*problem:(adsbygoogle = window.adsbygoogle || []).push({});

In the Niagara Falls hydroelectric generating plant, the energy of falling water is converted into electricity. The height of the falls is about 45 meters. Assuming that the energy conversion is highly efficient, approximately how much energy is obtained from one kilogram of falling water? Therefore, approximately how many kilograms of water must go through the generators every second to produce a megawatt of power (106 watts)?

____kg/s

*formulas:

Gravitational energy = (mass) × g × (height).

*attempts:

I tried to find energy based on the fact one drop of water is one gram.

I ended up pluging in the values and got (45)(9.8) = 441

I found this to be incorrect.

Not sure how to relate mass to seconds to energy to height....

=/

**Physics Forums - The Fusion of Science and Community**

# Energy...niagra falls problem...water

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Energy...niagra falls problem...water

Loading...

**Physics Forums - The Fusion of Science and Community**