Enthelpy change in isentropic condition (air-con)

Click For Summary
The discussion focuses on determining the enthalpy (h2) for refrigerant-134a under isentropic conditions at a pressure of 0.8 MPa. Participants note that while the saturated refrigerant table provides values for entropy (s) and pressure (p), the specific enthalpy is not directly available. It is suggested that the enthalpy should fall between 286.71 and 296.82 kJ, but a solution indicates a value of 275.39 kJ, prompting questions about the accuracy of the tables used. Differences in physical property values are acknowledged, with one participant referencing an older edition of a textbook that aligns more closely with their findings. The conversation highlights the importance of using the correct version of reference materials for accurate calculations.
yecko
Gold Member
Messages
275
Reaction score
15
Homework Statement
How to get h2?
(see pic)
Relevant Equations
isentropic
dH = dQ + Vdp = Tds + Vdp
H = U + pV
48nCmSj.png


h and s can be obtained from "Saturated refrigerant-134a—Pressure table"

however, how to get h2? it is not on the curve, and neither p or dV is given in the question. Thank you
 
Physics news on Phys.org
Ity says P 0.8 MPa on the curve ! You have s,p and can look up T in table A-13
 
1583933825540.png


This is table A13, which at P=0.8MPa, s=0.94456, h should be somewhere between 286.71 and 296.82.
However, from the solution, h= 275.39kJ, am I looking at the table in a correct way?
 
Yes you are. Turns out the phys props have changed slightly.
I have an older edition (2002) of cengel and there it matches better.
40273.660.9374
50284.390.9711

https://www.egr.msu.edu/classes/me417/somerton/R134a Tables.pdf

I googled "and operates on an ideal vapor-compression refrigeration cyle between 0.14 and 0.8 MPa" and did indeed find other results too.
 
Last edited:
  • Like
Likes yecko
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K