EOM for Pendulum hanging from spring

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SUMMARY

The discussion focuses on deriving the equations of motion (EOM) for a pendulum attached to a spring, utilizing both Newtonian and Lagrangian mechanics. The user successfully formulated the Lagrangian EOM but encountered difficulties with the Newtonian approach, specifically in summing forces and torques. The equations derived include my'' - ky + mg = 0 for vertical forces and mL²θ'' + mgLsin(θ) = 0 for torques. The user seeks clarification on completing the Newtonian solution and understanding the relationship between the two methods.

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Homework Statement


Derive Newton's and Lagrange's equation of motion for the system. Discuss differences and show how Newton's equations can be reduced to lagrange's equations. Assume arbitrarily large θ.

The system is a pendulum consisting of a massless rod of length L with a mass m attached to the end. The point of rotation is attached to a spring of stiffness k which is then attached to the ceiling and constrained to move in the y direction.

I have acquired what i believe to be the solution for the Lagrange EOM but am hung up on the Newtonian solution.

Homework Equations


Newtonian mechanics

The Attempt at a Solution


summing forces in the y direction i get my''-ky+mg=0 and summing toques about the rotation point i get mL2θ''+mgLsin(θ)=0

i defined positive y as going upward and positive moments as counterclockwise

I feel like this is incomplete and I am missing something.

For reference the lagrange EOM i got is 0=ML2θ'' + mLsin(θ)y'' + mLcos(θ)y'θ' - mL2θ'-mLsin(θ)y'
 
Last edited:
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The set up looks like this diagram, with the spring's motion being confined to the y direction:

upload_2015-3-17_20-2-28.png
 

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