Equation for the reaction between YO2 and water.

In summary, the conversation discusses the reaction between the non-metal oxide YO2 and water, with a proposed equation of YO2 + H2O ---> H2YO3. However, it is clarified that the correct formula for yttrium oxide is Y2O3 and it is sparingly soluble in water. The use of "Y" in the formula may stand for "unknown".
  • #1
Fusilli_Jerry89
159
0

Homework Statement


YO2 is a non-metal oxide. Write the equation for the reaction between YO2 and water.


Homework Equations


N/A


The Attempt at a Solution


YO2 + H2O ---> H2YO3

That is my guess, but I'm not sure if the numbers 2 and 3 in the product are correct, or if the product is even correct.
 
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  • #2
Actually, nothing is correct... including the question. There is no such thing as YO2. The formula for yttrium oxide is Y2O3. Add water to that... nothing happens. Yttrium oxide is sparingly soluble in water.
 
  • #3
Unless Y stands just for "unknown"...
 
  • #4
im pretty sure it means unknown
 
  • #5
So your equation looks OK.
 

FAQ: Equation for the reaction between YO2 and water.

What is the equation for the reaction between YO2 and water?

The equation for the reaction between YO2 and water is YO2 + 2H2O --> 2H+ + YO42-, where Y represents a metal element.

Is this a balanced equation?

Yes, this equation is balanced as there are equal numbers of atoms on both sides of the equation.

What is the role of Y in this reaction?

Y is a metal element that reacts with water to form a metal hydroxide and hydrogen ions.

What is the state of matter of YO2 and water in this reaction?

YO2 is a solid and water is a liquid in this reaction.

What type of reaction is this?

This is a single displacement or redox reaction, where YO2 donates electrons to water to form hydrogen ions.

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