Equation of motion canoe stroke

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Homework Help Overview

The discussion revolves around the equation of motion for a canoe stroke in the context of canoeing sport, focusing on the forces acting on the canoe and crew. Participants explore the relationships between propulsive force, drag force, and the velocities of the boat and crew.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt to derive the equation of motion using Newton's second law and discuss the relative velocities of the crew and the boat. Questions arise regarding the definitions of forces and the reference frame used for velocities.

Discussion Status

There is an ongoing exploration of the correct formulation of the equation, with some participants suggesting that the crew's velocity should be considered relative to the boat. Clarifications about the mass of the crew and paddles are being discussed, and some guidance has been offered regarding the separation of forces.

Contextual Notes

Participants note the need for clarity on whether the crew's velocity is absolute or relative, which affects the formulation of the equation. There is also mention of conflicting information from a book and scientific papers, leading to further questioning of the established equations.

The-alexandra
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Homework Statement



What is the equation of motion of canoe stroke in canoeing sport

Homework Equations



F=ma
Momentum=mV

The Attempt at a Solution




My

P - DT = MT (dVcrew/dt + dVboat/dt)



the Book response,

P - DT = (m dVboat/dt ) + MT (dVcrew/dt + dVboat/dt)

P=Propulsive force ; Vboat= Boat velocity
DT= Total drag force ; Vcrew= Crew velocity
m=Boat mass ; MT=Total mass ( boat + crew + paddle)

thanks for your help

Alexandra
 
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The-alexandra said:

Homework Statement



What is the equation of motion of canoe stroke in canoeing sport

Homework Equations



F=ma
Momentum=mV

The Attempt at a Solution




My

P - DT = MT (dVcrew/dt + dVboat/dt)



the Book response,

P - DT = (m dVboat/dt ) + MT (dVcrew/dt + dVboat/dt)

P=Propulsive force ; Vboat= Boat velocity
DT= Total drag force ; Vcrew= Crew velocity
m=Boat mass ; MT=Total mass ( boat + crew + paddle)

thanks for your help

Alexandra

Welcome to PF, The-alexandra! :smile:

I'm afraid neither your nor the book's response is right.

For the proper response it is necessary to know whether the crew velocity is relative to the boat, or whether it is an absolute velocity.
Can you tell?
 
Hi, I cannot find the answer

(Copy and paste)Book;

According to Newton’s second law, a linear force, F, generated by a system can be given by
ƩF=ma (1)

where m is the mass of the system and a is its acceleration. If input forces and masses of a system are known, then the velocity, V, of that system can be calculated as the integral of the system acceleration, such that
V=∫a dt (2)

In the case of the canoe stroke, equation (1) can be further developed, giving

P - DT = (m dVboat/dt ) + MT (dVcrew/dt + dVboat/dt)

P=Propulsive force ; Vboat= Boat velocity
DT= Total drag force ; Vcrew= Crew velocity
m=Boat mass ; MT=Total mass ( boat + crew + paddle)

where P is the total propulsive force, D is the total drag force, m is the mass of the boat , M is the combined mass of the boat, paddlers and paddles, vboat is the horizontal velocity of the boat relative to the Earth and vcrew is the horizontal velocity of the paddler’s centre of mass relative to the boat.

Someone can help me, Please I m lost :wink:
 
Last edited:
Good. So indeed the crew velocity is relative to the boat.

We want to do everything in the same frame of reference, for which we typically use the Earth frame.
So the actual crew velocity relative to the Earth is ##V_{crew} + V_{boat}##.

The paddles are not consistently mentioned, but I'll assume they move together with the paddlers.The forces need to be charted separately, taking each object, its mass, and its velocity into account separately.

The force on the boat is ##F_{boat} = m_{boat} {dV_{boat} \over dt}## and the force on the crew+paddles is ##F_{crew+paddles} = m_{crew+paddles} {d(V_{crew} + V_{boat}) \over dt}##.

Since the mass ##m_{crew+paddles}## is not given, we will replace it by ##M_T - m_{boat}##, which is the same.Can you add those 2 forces together and simplify the resulting expression?
 
thanks so much for your help, :smile: "I like Serena " :smile:
I'm really sorry, but i can't find the same answer:
for the right side of the equation

=(mboat dVboat/dt ) + (MT−mboat)((dVcrew/dt + dVboat/dt))

=MT(dVcrew/dt + dVboat/dt) - mboat dVcrew/dt


could you tell, please where is my mistake?

thanks so much, I really appreciate your help

Alexandra
 
No mistake.
That is the proper answer! :wink:

I said before that the Book's response was wrong.
 
Last edited:
I'm sorry, I found the same equation in two scientific paper, and we are wrong,
http://www.worldacademicunion.com/jo...o03paper01.pdf

you have 5 more minutes for help me ??

thanks again
 
Last edited by a moderator:
Well, I claim the paper is wrong. :rolleyes:

Actually, I think they made a typo.
The text should read: "M is the combined mass of the paddlers and the paddles"

instead of: "M is the combined mass of the boat, paddlers and paddles"

With this correction the formula would be right.EDIT: Am I still in time?
 
  • #10
yes, you are in time.. for save the science

thanks again and have a nice day =)
 

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