What Is the Equilibrium Concentration of CO in the Reaction at 400K?

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SUMMARY

The equilibrium concentration of CO in the reaction CO(g) + NH3(g) → HCONH2(g) at 400K is determined using the equilibrium constant K = 0.207. Given initial concentrations of 2.20 M for CO and 2.60 M for NH3, the equilibrium concentration of CO is calculated to be 0.44 M. The calculation involves solving the equation 0.207 = (X) / ((2.20 - X)(2.60 - X)), leading to the valid root of 1.76 for X, which results in a positive concentration for CO.

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Homework Statement



CO(g) + NH_3(g) ...> HCONH_2(g)

euilibrium constant is: K = 0.207 at 400 K
If a reaction is filled with intial concentrations 2.20 M of CO and 2.60 M of NH_3 and the reactanats are allowed to raect at 400K/ what will be the concentrations of CO at equilibrium ?


Homework Equations



Keq = [HCONH_2] / [CO] [NH_3]

The Attempt at a Solution




0.207 = (X) /(2.20-X)(2.6-X)

But I'm getting the wrong answer for x. Please help me.
 
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^your equation for x seems correct. i rearranged it to
0 = 5.72/x - 5.007 + x
we need to find the zeroes

when graphed, the zeros are 1.76 and 3.24

if we use 3.24, we would have a negative concentration of both CO and NH3, which is physically impossible. so, we go with 1.76

so the answer: 2.2 M - 1.76 = 0.44 M
 

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