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## Homework Statement

A 7.0kg ladder is placed against a smooth wall so that it makes an angel of 72deg to the horizontal. A 56kg person stands 4.0m from the bottom of the ladder.

What force does the wall exert on the ladder?

What is the coefficient of friction between the ladder and the ground?

## Homework Equations

EFy=0 : Fy=69+540

EFx=0: Fx=Fwall

ET=0: (5.71Fwall)= (69*0.93)+(540 * 1.23)

Fwall=129.5N

Ffriction = uFnormal

## The Attempt at a Solution

Force exerted by wall is 129.5N. Friction force is therefore 129.5N

Stuck as to what force is the normal force used to calculate coefficient of friction.