Ladder Leaning against wall -- find the coefficient of friction

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Pedgepoke
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Homework Statement



Ladder leans against wall at angle θ. It is L meters long and mass m. Find the coefficient of friction with the floor. Assume no friction at the top.[/B]

Homework Equations


ΣFx = 0
ΣFy = 0
Στ = 0
ƒ = μFn (Fn being the normal force with the ground)

The Attempt at a Solution



1. Drew free body diagram
2. Broke vectors into their respective sin and cos parts
3. Ended up with 4 complicated equations, 4 unknowns
4. Super complicated answer with a lot of sin, cos that are not solvable. Am I doing this right??

help
 
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Pedgepoke said:
Ladder leans against wall at angle θ. It is L meters long and mass m. Find the coefficient of friction with the floor. Assume no friction
Not enough information. I presume it also says the ladder is on the point of slipping, or maybe it actually asks for a lower bound on the coefficient.
Pedgepoke said:
Am I doing this right??
Doesn't sound like it, but not possible to help further without seeing your work.
Please post as typed in algebra, not an image.
 
As haruspex noted, you need to be more specific in your problem statement. Is this ladder on the verge of slipping? Are you looking for a range of angles where the ladder will not slip? How about when someone tries to climb the ladder? There may be a maximum height they can climb before slippage.
 
Show your working. You might have missed some issues implied in the problem statement. For example zero friction at the wall means the reaction force there must be horizontal.
 
I would think you would end up with 3 equations since this is a static equilibrium problem in the x-y plane. ΣF(x) = 0, ΣF(y) = 0, Στ(z) = 0, τ = r x F,
 
Dr Dr news said:
I would think you would end up with 3 equations since this is a static equilibrium problem in the x-y plane. ΣF(x) = 0, ΣF(y) = 0, Στ(z) = 0, τ = r x F,
Judging from post #1, it may be that Ff=μN is being counted as a separate equation.