Equilibrium - Ladder against wall

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SUMMARY

The discussion centers on calculating the forces acting on a 7.0 kg ladder leaning against a smooth wall at a 72-degree angle. The force exerted by the wall on the ladder is determined to be 129.5 N. Additionally, the friction force is equal to the wall force, also 129.5 N. The participants express confusion regarding the normal force necessary to calculate the coefficient of friction between the ladder and the ground.

PREREQUISITES
  • Understanding of static equilibrium conditions (EFx=0, EFy=0)
  • Knowledge of force components and angles in physics
  • Familiarity with the concept of friction and the coefficient of friction
  • Basic grasp of ladder mechanics and forces acting on inclined objects
NEXT STEPS
  • Calculate the normal force acting on the ladder using EFy=0
  • Determine the coefficient of friction using Ffriction = uFnormal
  • Explore the implications of ladder angle on stability and force distribution
  • Review examples of similar problems involving inclined planes and static friction
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and static equilibrium, as well as educators seeking to clarify concepts related to forces on inclined objects.

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Homework Statement


A 7.0kg ladder is placed against a smooth wall so that it makes an angel of 72deg to the horizontal. A 56kg person stands 4.0m from the bottom of the ladder.

What force does the wall exert on the ladder?
What is the coefficient of friction between the ladder and the ground?

Homework Equations



EFy=0 : Fy=69+540
EFx=0: Fx=Fwall
ET=0: (5.71Fwall)= (69*0.93)+(540 * 1.23)
Fwall=129.5N

Ffriction = uFnormal

The Attempt at a Solution



Force exerted by wall is 129.5N. Friction force is therefore 129.5N

Stuck as to what force is the normal force used to calculate coefficient of friction.
 
Physics news on Phys.org
canicon25 said:
EFy=0 : Fy=69+540
What about the force from the floor? (That's the missing normal force.)
 
Thanks
 

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