Equivalence Classes Explaination

Click For Summary
SUMMARY

This discussion focuses on understanding equivalence classes and their properties within the context of discrete mathematics. The key steps to determine an equivalence class involve verifying the properties of reflexivity, symmetry, and transitivity of a relation. An example provided illustrates how to visualize equivalence classes using the analogy of cow particles, where particles are equivalent if they belong to the same section of the cow. The conclusion emphasizes that equivalence relations partition a set into mutually disjoint subsets, and understanding this concept simplifies the study of equivalence classes.

PREREQUISITES
  • Understanding of reflexive, symmetric, and transitive properties in relations
  • Familiarity with discrete mathematics concepts
  • Basic knowledge of set theory and partitions
  • Ability to visualize mathematical concepts
NEXT STEPS
  • Study the properties of equivalence relations in detail
  • Explore examples of equivalence classes in different mathematical contexts
  • Learn about partitions and their relationship to equivalence relations
  • Practice problems involving equivalence relations and their visual representations
USEFUL FOR

Students of discrete mathematics, educators teaching equivalence relations, and anyone seeking to enhance their understanding of mathematical partitions and visual learning techniques.

Sinister
Messages
32
Reaction score
0
I'm wondering if someone could briefly explain how I can determine the equivalence class of relation?

I understand that first you must test the relation to see if is true for the properties, reflexive, symmetric, and transitive. But my main problem is once that is done how can I get the equivlant class of that.

My book that I'm using does a terrible job in explaining the theorem, and hence it is very difficult for me to solve the practice problems.

Thanks!
 
Physics news on Phys.org
Do you understand what the definition of equivalence class is but are confused about how to picture it / describe it? If this is the case, then it would help if you posted an example of the problem that you're working on, since it is difficult in general to get a good picture of what an equivalence class looks like.
 
Yeah, I'm a very visual learner (hence why discrete math isn't my strongest subject), I try to picture a lot of problems and I find that helps me to 1) understand/memorize concepts easily and 2) apply the knowledge in tests. Anyways,

I was working on this problem and it drove me crazy until I had to look at the solution manual:

1) Define P on the set R × R of ordered pairs of real numbers
as follows: For all (w, x), (y, z) ∈ R × R,
(w, x) P (y, z) ⇔ w = y.2) Let A be the set of all statement forms in three variables
p, q, and r . R is the relation defined on A as follows: For
all P and Q in A,
P R Q ⇔ P and Q have the same truth table.
 
Sinister said:
Yeah, I'm a very visual learner (hence why discrete math isn't my strongest subject), I try to picture a lot of problems and I find that helps me to 1) understand/memorize concepts easily and 2) apply the knowledge in tests.

Then you're in luck, because there's a totally simple visualization of equivalence classes. Just to pick an example, ever see one of those photos of a cow that shows which cuts of meat come from which part of the cow?

Here's a perfect one.

http://bastropcattlecompany.com/catalog/images/cow-anatomy.gif

Now let's define an equivalence class based on this pic. Let's say that our set is the set of cow particles, where a particle is just some tiny part of the cow -- like a molecule, say.

Two cow particles x and y are equivalent if they are in the same section of the cow.

Is this reflexive? Symmetric? Transitive? Yes, yes, and yes, but you should walk through the logic for yourself. Write down the proof that the relation of two cow molecules being in the same numbered section is an equivalence relation.

That's all an equivalence relation is. It's a partition of a set into a collection of mutually disjoint subsets. Every element of the set goes to exactly one subset; and each of the subsets is an equivalence class.

In other words if you have any equivalence relation, and for some element x you defined the equivalence class of x, denoted [x], as the set of all elements that are equivalent to x; then the set of all the equivalence classes are a partition of the original set.

Another way to say this is that if you have two equivalence classes [a] and , then either [a] = or [a] and are disjoint. You should prove that.

An equivalence relation gives you a partition; and every partition gives you an equivalence relation. Equivalence classes and partitions are just two ways of looking at the same thing.

Once you get this, equivalence relations are easy. And it's totally visual.

[Note: I think that's a bull, not a cow. Fortunately we're not on the Biology forum]
 
Last edited:
If there are an infinite number of natural numbers, and an infinite number of fractions in between any two natural numbers, and an infinite number of fractions in between any two of those fractions, and an infinite number of fractions in between any two of those fractions, and an infinite number of fractions in between any two of those fractions, and... then that must mean that there are not only infinite infinities, but an infinite number of those infinities. and an infinite number of those...

Similar threads

Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
8K