Equivalence point in acid-base titration

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SUMMARY

In acid-base titration, the equivalence point varies depending on the strength of the acid and base involved. For strong acid-strong base titrations, the equivalence point occurs at pH 7 due to the neutralization reaction producing a non-hydrolyzing salt. Conversely, weak acid-strong base titrations yield a pH greater than 7, while strong acid-weak base titrations result in a pH less than 7. The pH at the equivalence point is influenced by the hydrolysis of the salt formed during the reaction, as demonstrated by specific examples such as HCl with NaOH, HOAc with NaOH, and NH4OH with HCl.

PREREQUISITES
  • Understanding of acid-base chemistry
  • Familiarity with pH scale and measurements
  • Knowledge of hydrolysis and its effects on pH
  • Experience with titration techniques
NEXT STEPS
  • Study the concept of hydrolysis in detail
  • Learn about the dissociation constants (Ka and Kb) of various acids and bases
  • Explore the use of pH meters in titration
  • Investigate the effects of different indicators on titration results
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Chemistry students, laboratory technicians, educators, and anyone involved in analytical chemistry or titration techniques will benefit from this discussion.

Tony Stark
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In acid base titration, we try to neutralize the analyte by adding sufficient titrant and observing the color change in the indicator.
But if the analyte is neutralized, then it must always be at ph 7. Why is it that we use indicator of different ranges to check equivalence point?
 
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We can and many laboratory practitioners do use a pH meter to watch for the endpoint.

pH 7 endpoint would be for titrating strong acid or base, with strong base or acid.

Why to pH 7?
Look at the water dissociation constant.
(H+)(OH-)=1.0*10-14
 
For titration of ...
Strong Acid + Strong Base => Equiv Pt pH = 7 b/c the ions of the salt formed do not hydrolyze. Example: HCl + NaOH => NaCl + H2O ... NaCl => Na+ + Cl- ... Na+ + H2O => No Rxn and Cl- + H2 => No Rxn. Consequently the pH depends solely upon the autoionization of water;i.e. H2O => H3O+ + OH- and Kw = [H3O+][OH-]. [H3O+] = [OH-] = 1 X 10-7M => Kw = [10-7][10-7] = 1x10-14 ... and, pH = -log[H3+] = -log(10-7) = 7

A Weak Acid + Strong Base => Equiv Pt pH > 7 b/c the anion of the salt formed hydrolyzes leaving an excess OH- in solution at equivalence point. Example: HOAc + NaOH => NaOAc + H2O ... NaOAc => Na+ + OAc- ... Na+ + H2O => no rxn ... OAc- + 2H2O => HOAc + OH- ... The excess OH- leaves the pH at equivalence point ~ 8.90 for a mix of equal volumes of a 0.10M HOAc + 0.10M NaOH reaction.

A Strong Acid + Weak Base => Equiv Pt pH < 7 b/c the cation of the salt formed hydrolyzes leaving an excess of H3O+ ions in solution at the equivalence point. Example: NH4OH + HCl => NH4Cl + H2O ... NH4Cl => NH4+ + Cl- ... NH4+ + 2H2O => NH4OH + H3O+ ... The excess H3O+ => pH ~ 5.0 for a mix of equal volumes of 0.10M NH4OH + 0.10M HCl.

A Weak Acid + Weak Base at Equiv Pt is dominated by the electrolyte with the larger Keq value. That is, if Kb > Ka => pH > 7 at Equiv Pt, and if Kb < Ka => pH < 7 at Equiv Pt.
 

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