For titration of ...
Strong Acid + Strong Base => Equiv Pt pH = 7 b/c the ions of the salt formed do not hydrolyze. Example: HCl + NaOH => NaCl + H2O ... NaCl => Na+ + Cl- ... Na+ + H2O => No Rxn and Cl- + H2 => No Rxn. Consequently the pH depends solely upon the autoionization of water;i.e. H2O => H3O+ + OH- and Kw = [H3O+][OH-]. [H3O+] = [OH-] = 1 X 10-7M => Kw = [10-7][10-7] = 1x10-14 ... and, pH = -log[H3+] = -log(10-7) = 7
A Weak Acid + Strong Base => Equiv Pt pH > 7 b/c the anion of the salt formed hydrolyzes leaving an excess OH- in solution at equivalence point. Example: HOAc + NaOH => NaOAc + H2O ... NaOAc => Na+ + OAc- ... Na+ + H2O => no rxn ... OAc- + 2H2O => HOAc + OH- ... The excess OH- leaves the pH at equivalence point ~ 8.90 for a mix of equal volumes of a 0.10M HOAc + 0.10M NaOH reaction.
A Strong Acid + Weak Base => Equiv Pt pH < 7 b/c the cation of the salt formed hydrolyzes leaving an excess of H3O+ ions in solution at the equivalence point. Example: NH4OH + HCl => NH4Cl + H2O ... NH4Cl => NH4+ + Cl- ... NH4+ + 2H2O => NH4OH + H3O+ ... The excess H3O+ => pH ~ 5.0 for a mix of equal volumes of 0.10M NH4OH + 0.10M HCl.
A Weak Acid + Weak Base at Equiv Pt is dominated by the electrolyte with the larger Keq value. That is, if Kb > Ka => pH > 7 at Equiv Pt, and if Kb < Ka => pH < 7 at Equiv Pt.