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So I'm writing some code for a project and I'm stuck on the first part. This code is obviously unfinished, but I tried testing it just to see how it was coming along and I kept getting the [Error] too few arguments to function 'output_short_format'. As far as I can tell, I'm passing three arguments into the function which takes three arguments. I don't see the problem.
C:
#include <stdio.h>
#include <math.h>
void output_short_format (double, double, double);
int main () {
int x, amount, int_rate, term, mon_int_rate;
printf ("Welcome to Mortgage Calculator!\nPlease select from the options below.\n\n");
printf ("For 'Short Format' press 1\n\nFor 'Amortized Schedule' press 2\n\nFor 'Monthly Early Payments' press 3\n\nFor 'Yearly Early Payments' press 4\n\n");
printf ("Where would you like to go? ");
scanf ("%d", &x);
if (x=1) {
system ("cls");
printf ("---------------------------------\n");
printf (" LOAN TERMS\n");
printf ("---------------------------------\n");
amount = 150000;
int_rate = 4;
term = 15;
printf ("Loan Amount: %15d\n", amount);
printf ("Interest Rate: %12d%%\n", int_rate);
printf ("Term: %16d years\n", term);
printf ("---------------------------------\n\n");
mon_int_rate = int_rate/1200;
output_short_format (double amount, double mon_int_rate, double term);
}
}
void output_short_format (double loan_amount, double interest_rate, double term_years) {
int months, p;
months = term_years*12;
p = (loan_amount*interest_rate*pow (1+interest_rate, months))/(pow (1+interest_rate, months)-1);
printf ("Monthly payment is: %12d", p);
printf ("Total interest is: %12d", interest_rate); \\ignore
printf ("Total amount paid is: %12d", term_years); \\ignore
}
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