Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Ti89 Titanium too few arguments

  1. Oct 29, 2011 #1
    Ti89 Titanium "too few arguments"

    sorry for my noobieness, but I'm having problem with my mod( function on my Ti89 Titanium

    On other calcs: 54 mod 10 = 4
    like here: http://www.google.com/search?q=54+mod+10

    But when i use the mod( function I either get "to few arguments" og just the result 54.mod10

    can anyone point me to what I'm doing wrong?
     
    Last edited by a moderator: Oct 30, 2011
  2. jcsd
  3. Oct 29, 2011 #2

    I like Serena

    User Avatar
    Homework Helper

    Re: Ti89 Titanium qustion

    Welcome to PF, Spagnum! :smile:

    Have you tried mod(54,10)?
     
  4. Oct 29, 2011 #3
    Re: Ti89 Titanium qustion

    Thank you!

    yes I have - that just results in "Too few arguments"
     
  5. Oct 29, 2011 #4

    I like Serena

    User Avatar
    Homework Helper

  6. Oct 29, 2011 #5
    Re: Ti89 Titanium qustion

    Yup I been to that page myself but I get the same result.(Too few arguments) I even reset the calculator, in case it had something to do with some settings.
     
  7. Oct 29, 2011 #6

    I like Serena

    User Avatar
    Homework Helper

    Re: Ti89 Titanium qustion

    The one reason I can think it might say "too few arguments", is if there's a problem with the decimal point, in which case you'd have tried to calculate mod(54.10, ???)
    You sure you used a comma?
    Or perhaps you could try a semicolon?
     
  8. Oct 29, 2011 #7
    Re: Ti89 Titanium qustion

    ofc... the comma. :blushing:
    I'm so use to working in Excel where . is the comma, and haven't used my calculator in ages.

    Anyways it works like a charm now, thanks a lot for your help Serena!
     
  9. Oct 29, 2011 #8

    I like Serena

    User Avatar
    Homework Helper

    Re: Ti89 Titanium qustion

    You're welcome! :smile:
     
  10. Oct 29, 2011 #9

    Borek

    User Avatar

    Staff: Mentor

    Re: Ti89 Titanium qustion

    On my TI-89 (but not Titanium) mod(54,10) gives correct 4.
     
  11. Oct 29, 2011 #10

    jtbell

    User Avatar

    Staff: Mentor

    Re: Ti89 Titanium qustion

    The old UK versus USA, comma versus period switcheroo, eh? :rolleyes:
     
  12. Oct 29, 2011 #11

    I like Serena

    User Avatar
    Homework Helper

    Re: Ti89 Titanium qustion

    Uhh :uhh: I've never heard of using a period as an argument separator? :confused:
     
  13. Feb 18, 2012 #12
    Re: Ti89 Titanium "too few arguments"

    Hey I am also a noob and I need help.
    I made this program to calculate the area of a sector and I keep getting "Too Few Arguments"
    The ø is a theta and the 'arrow' is the arrow made by STO


    area_sec()
    Prgm
    Local a,r,g,s,ø,k
    Dialog
    Request "Press 1 if you have rs and 2 if you have rø"a
    EndDlog
    If a=1 Then
    Dialog
    Request "Enter r",r
    Request "Enter s",s
    EndDlog
    expr(-r) 'arrow' r
    expr(s) 'arrow' s
    (1/2)*r*s 'arrow' k
    Disp "Area is"&string(k)
    Else If a=2 Then
    Dialog
    Request "Enter r",r
    Request "Enter ø",ø
    Dialog
    expr(-r) 'arrow' r
    expr(s) 'arrow' s
    (1/2)*r*r*ø 'arrow' k
    Disp "Area is"&string(k)
    Else
    EndIf
    DelVar a,r,s,ø,k
    EndPrgm
     
  14. Aug 4, 2012 #13
    Re: Ti89 Titanium "too few arguments"

    Look at line 5 again:

    You forgot a comma in between your "request" and your variable, like so:

    Code (Text):
    Request "Press 1 if you have rs and 2 if you have rø"[B],[/B]a
    Try that and see what you get.
     
  15. Mar 7, 2014 #14
    SonikkuUSA is right about the comma. Also, after the first "EndDlog", you have to add "expr(a)->a". This is because request (and any dialog function) is treated as a string, and we want a value. Also, in the first request, type"Request"Words",a,0. The zero will turn alpha-lock off in that box so you don't have to hit the alpha button every time you want to type 1.

    Instead of using delvar at the end, you could just use local and define all of the variables at the beginning, too.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Ti89 Titanium too few arguments
  1. Ti89 titanium (Replies: 16)

  2. Ti89 titanium graphing (Replies: 1)

Loading...