Euler equations for ideal fluids, approximations

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SUMMARY

The discussion focuses on the Euler equations for ideal compressible flow, specifically the approximations made using small-value expansions for density and pressure. The equations are transformed to express the time derivative of velocity and density in terms of the perturbations from their mean values. The key point of confusion arises from the simplification where the term involving the perturbation in density, \(\delta \rho \nabla \cdot v\), is deemed negligible compared to \(\rho_0 \nabla \cdot v\) due to the condition \(\delta \rho << \rho_0\).

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Niles
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Homework Statement

The Euler equations for ideal compressible flow are given by
<br /> \partial_t v + (v\cdot \nabla)v = g-\frac{1}{\rho}\nabla p \\<br /> \partial_t \rho + \nabla \cdot(\rho v) = 0<br />
In my book these are written in terms of the small-value expansions \rho = \rho_0 + \delta \rho, p = p_0 + \delta p and the equations become
<br /> \partial_t v = -\frac{1}{\rho_0}\nabla \delta \rho \\<br /> \partial_t (\delta \rho) = -\rho_0 \nabla \cdot v<br />

In the second equation, I don't understand why the RHS becomes \rho_0 \nabla \cdot v instead of (\rho_0+\delta \rho) \nabla \cdot v?

Thanks in advance.
 
Physics news on Phys.org
\delta \rho \nabla \cdot v is negligible compared to \rho_0 \nabla \cdot v because \delta \rho &lt;&lt; \rho_0
 

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