MHB Evaluate Piecewise-Defined Function....1

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The discussion focuses on evaluating a piecewise-defined function with two segments: y = -x^2 for -2 < x ≤ 0 and y = x/2 for 0 < x ≤ 4. When x = 0, the upper piece yields y = 0, and when x = 4, the bottom piece gives y = 2. The evaluations are confirmed to be correct. The poster expresses satisfaction with the accuracy and plans to share more questions from a precalculus textbook in the future.
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The following function is a piecewise-defined function.

y = -x^2 if -2 < x ≤ 0...upper piece
y = x/2 if 0 < x ≤ 4.. bottom piece

Evaluate when x = 0 and x = 4.

Solution:

For x = 0, we evaluate the upper piece.

y = -(0)^2

y = 0

For x = 4, we evaluate the bottom piece.

y = 4/2

y = 2

Is this correct?
 
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Yes, this is correct.
 
It feels good to be correct. More questions will be posted tomorrow as I travel through David Cohen's precalculus textbook.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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