MHB Evaluate Piecewise-Defined Function....1

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The discussion focuses on evaluating a piecewise-defined function with two segments: y = -x^2 for -2 < x ≤ 0 and y = x/2 for 0 < x ≤ 4. When x = 0, the upper piece yields y = 0, and when x = 4, the bottom piece gives y = 2. The evaluations are confirmed to be correct. The poster expresses satisfaction with the accuracy and plans to share more questions from a precalculus textbook in the future.
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The following function is a piecewise-defined function.

y = -x^2 if -2 < x ≤ 0...upper piece
y = x/2 if 0 < x ≤ 4.. bottom piece

Evaluate when x = 0 and x = 4.

Solution:

For x = 0, we evaluate the upper piece.

y = -(0)^2

y = 0

For x = 4, we evaluate the bottom piece.

y = 4/2

y = 2

Is this correct?
 
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Yes, this is correct.
 
It feels good to be correct. More questions will be posted tomorrow as I travel through David Cohen's precalculus textbook.
 

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