- #1

karush

Gold Member

MHB

- 3,269

- 5

Evaluate $I=\displaystyle\int_1^3 \dfrac{y^3-2y^2-y}{y^2}\ dy$

\begin{array}{lll}\displaystyle

\textit{expand}

&I=\displaystyle\int_1^3 y \ dy

-\displaystyle\int_1^3 2 \ dy

-\displaystyle\int_1^3 \dfrac{1}{y} \ dy

\end{array}

just want to see if I am on the right horse before I cross the stream