Even and odd function question

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The discussion centers on proving that the only function that is both even and odd is f(x)=0. Participants explore the implications of a function being both even and odd, leading to the conclusion that if f(x) is not zero for all x, it cannot satisfy both conditions. The proof involves showing that if a function has a non-zero coefficient, it will be either even, odd, or neither. Suggestions include using proof by contradiction and examining cases based on the sign and value of the coefficient. Ultimately, the consensus is that the only solution is the zero function.
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Homework Statement



Show that the only function which is both even and odd is f(x)=0

2. The attempt at a solution

Since f(x)=0 is f(x)=0x it is not hard to show that it is odd and even. In order to complete the proof I need to show that this is the only funcion. I know intuitively that if in f(x)=Ax A\neq0 then the function is always either odd, even or neither. How should I complete the proof? What should I write?

Maybe: "Since, it is obvious that if A\neq0 the function is either ... " But is it really that obvious? Should I use proof by exhaustion and show that in all posible cases this is true (when A is positive, negative, fraction)?
 
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If a function f is both odd and even, then f(-x)=f(x) and f(-x)=-f(x), so...
 
hi mindauggas! :smile:

start "suppose f(x) is not 0 for all x, then …" :wink:
 

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