Examples of Uniformly, point wise convergence

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This discussion focuses on examples of uniformly and pointwise convergent sequences of functions. The sequence defined by $\displaystyle s_{n} (x) = \sum_{k=0}^{n} (1-x)x^{k}$ converges pointwise to 1 for $0 \le x < 1$ and to 0 for $x=1$, illustrating pointwise convergence without uniform convergence on the interval [0,1]. Conversely, the sequence $$f_n(x)=x^n$$ demonstrates that while it is not uniformly convergent on [0,1), it is uniformly convergent on any closed subset $$[0,b] \subset [0,1)$$, as shown using the M-test.

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Amer
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I need some examples of sequences some converges uniformly and some point wise Thanks in advanced
 
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Amer said:
I need some examples of sequences some converges uniformly and some point wise Thanks in advanced

A very suggestive example is given by the sequence of functions...

$\displaystyle s_{n} (x) = \sum_{k=0}^{n} (1-x)\ x^{k}\ (1)$

For $0 \le x < 1$ is $\displaystyle \lim_{n \rightarrow \infty} s_{n} (x) = 1$ but for x=1 is $\displaystyle \lim_{n \rightarrow \infty} s_{n} (x) = 0$, so that $s_{n} (x)$ conveges pointwise in [0,1) but doesn't uniformly converge in [0,1)...

Kind regards

$\chi$ $\sigma$
 
If $$f_n(x)$$ is uniformally convergent then it is point-wise convergent. The difference is that uniform convergence is defined on sets.

Take for example the sequence of functions $$f_n(x)=x^n$$ on the interval $$[0,1)$$ this sequence is not uniformally convergent but any closed subset is. Essentially we can use the M-test to prove uniform convergence. Choose $$[0,b] \subset [0,1)$$ then we have the following

$$x^n \leq b^n \,\,\, \forall \,\, x \in [0,b]$$ since $$\lim b^n = 0 $$ .$$f_n $$ is uniformally convergent on $$[0,b]$$.
 

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