MHB Examples of Uniformly, point wise convergence

Amer
Messages
259
Reaction score
0
I need some examples of sequences some converges uniformly and some point wise Thanks in advanced
 
Physics news on Phys.org
Amer said:
I need some examples of sequences some converges uniformly and some point wise Thanks in advanced

A very suggestive example is given by the sequence of functions...

$\displaystyle s_{n} (x) = \sum_{k=0}^{n} (1-x)\ x^{k}\ (1)$

For $0 \le x < 1$ is $\displaystyle \lim_{n \rightarrow \infty} s_{n} (x) = 1$ but for x=1 is $\displaystyle \lim_{n \rightarrow \infty} s_{n} (x) = 0$, so that $s_{n} (x)$ conveges pointwise in [0,1) but doesn't uniformly converge in [0,1)...

Kind regards

$\chi$ $\sigma$
 
If $$f_n(x)$$ is uniformally convergent then it is point-wise convergent. The difference is that uniform convergence is defined on sets.

Take for example the sequence of functions $$f_n(x)=x^n$$ on the interval $$[0,1)$$ this sequence is not uniformally convergent but any closed subset is. Essentially we can use the M-test to prove uniform convergence. Choose $$[0,b] \subset [0,1)$$ then we have the following

$$x^n \leq b^n \,\,\, \forall \,\, x \in [0,b]$$ since $$\lim b^n = 0 $$ .$$f_n $$ is uniformally convergent on $$[0,b]$$.
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

Similar threads

Replies
22
Views
3K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 17 ·
Replies
17
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K