MHB Examples of Uniformly, point wise convergence

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The discussion provides examples of sequences that converge uniformly and pointwise. The sequence s_n(x) converges pointwise on the interval [0, 1) but does not converge uniformly on [0, 1]. In contrast, the sequence f_n(x) = x^n is not uniformly convergent on [0, 1) but is uniformly convergent on any closed subset [0, b] where b < 1. The M-test is mentioned as a method to establish uniform convergence. Overall, the thread highlights the distinction between pointwise and uniform convergence through specific function examples.
Amer
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I need some examples of sequences some converges uniformly and some point wise Thanks in advanced
 
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Amer said:
I need some examples of sequences some converges uniformly and some point wise Thanks in advanced

A very suggestive example is given by the sequence of functions...

$\displaystyle s_{n} (x) = \sum_{k=0}^{n} (1-x)\ x^{k}\ (1)$

For $0 \le x < 1$ is $\displaystyle \lim_{n \rightarrow \infty} s_{n} (x) = 1$ but for x=1 is $\displaystyle \lim_{n \rightarrow \infty} s_{n} (x) = 0$, so that $s_{n} (x)$ conveges pointwise in [0,1) but doesn't uniformly converge in [0,1)...

Kind regards

$\chi$ $\sigma$
 
If $$f_n(x)$$ is uniformally convergent then it is point-wise convergent. The difference is that uniform convergence is defined on sets.

Take for example the sequence of functions $$f_n(x)=x^n$$ on the interval $$[0,1)$$ this sequence is not uniformally convergent but any closed subset is. Essentially we can use the M-test to prove uniform convergence. Choose $$[0,b] \subset [0,1)$$ then we have the following

$$x^n \leq b^n \,\,\, \forall \,\, x \in [0,b]$$ since $$\lim b^n = 0 $$ .$$f_n $$ is uniformally convergent on $$[0,b]$$.
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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