Excited atom decaying to ground state

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Homework Help Overview

The discussion revolves around the concept of atomic decay and the emission of photons, specifically focusing on the color of light emitted when an excited atom decays to an intermediate state versus its ground state.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between energy levels and the frequency of emitted light, questioning how the energy difference affects the color of light emitted during atomic decay.

Discussion Status

There is an ongoing exchange of ideas regarding the energy-frequency relationship, with some participants suggesting that a smaller energy gap results in a higher frequency photon, while others challenge this notion, leading to a reconsideration of the implications of energy differences on emitted light color.

Contextual Notes

Participants are navigating the implications of the energy levels involved in atomic transitions and how these relate to the visible spectrum, with some confusion about the proportionality between energy and frequency.

Cataklyzm
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Hello.
I'm trying to grasp this concept. The question states:
An excited atom decays to its ground state and emits a photon of green light. If instead the atom decays to an intermediate state, what color of light might be emitted?

I have the electromagnetic spectrum with the visible lights broken down.
Am I supposed to understand that an atom decaying to an intermediate state wouldn't use as much energy as an atom decaying to ground state?
Something like E = hf. So because of the decrease in energy, there is an increase in frequency, so the emitted light might be Blue or Violet, which have higher frequencies than green?

Am I on the right track?

Thanks,

Cataklyzm
 
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Nope, if it decays into an intermediate state, then the energy gap b/w the levels will be smaller, hence the frequency of the radiated photon.

Daniel.
 
Ohh okay.
So the CHANGE in energy between the excited state and intermediate state is smaller than the change in energy between the excited state and the ground state.

So the equation: Change in energy = h * f provides:
A smaller change in energy creates a higher frequency photon.
Violet and blue have higher frequencies than green.
Therefore, the emitted light would be violet or blue.

Thank you.
 
No way, if the energy is smaller, then the frequency would be smaller, since they are directly proportional. So i'd say rather yellow or orange.

Daniel.
 
Ohhhh.. okay.
I don't know how I didn't see that.
because h is Planck's constant, difference in energy is proportional to frequency.. so it would be a lower frequency photon.. like red or orange..
Got it..
=)
Thanks
 

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