Suppose that the linear system Ax=b is given for some symmetric A, and it is known that vector c spans the null-space of A.(adsbygoogle = window.adsbygoogle || []).push({});

How could one formally show that if b is not orthogonal to c, the solution to the system Ax=b does not exist?

To remind you, the null-space of A contains all vectors u for which Au=0.

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# Existent solution to the linear system Ax=b

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