Expectation of a Joint Continuous rv

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SUMMARY

The discussion focuses on calculating the expectation E(XY) for a joint continuous random variable defined by the joint probability density function f(x,y) = 6(x-y) within the limits 0 < y < x < 1. The formula for expectation is clarified as E(g(X,Y)) = ∫ g(x,y)f(x,y) dy dx, where g(X,Y) is specified as XY. The integration limits are explicitly stated, guiding the calculation of the expected value.

PREREQUISITES
  • Understanding of joint probability density functions
  • Familiarity with double integrals in calculus
  • Knowledge of expectation in probability theory
  • Basic concepts of random variables and their distributions
NEXT STEPS
  • Study the properties of joint continuous random variables
  • Learn about calculating expectations using double integrals
  • Explore the concept of marginal distributions and their calculations
  • Investigate applications of joint distributions in statistical modeling
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Students and professionals in statistics, data science, and applied mathematics who are working with joint distributions and expectations in probability theory.

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fx,y = 6(x-y)dydx, if 0<y<x<1

how do you find E(XY),
i know the formula...g(x,y)fxy(x,y)dydx

but i don't know what 'g(x,y)' represents and the limits to use??
 
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The expectation of g(X,Y) is \mathbb{E}(g(X,Y)):= \int g(x,y)f(x,y)\mathrm{d}x\mathrm{d}y

with the integral being taken over the whole of the probability space of X and Y.

So here, g(X,Y) is XY, and the limits are given to you: 0<y<x<1.
 
If there are an infinite number of natural numbers, and an infinite number of fractions in between any two natural numbers, and an infinite number of fractions in between any two of those fractions, and an infinite number of fractions in between any two of those fractions, and an infinite number of fractions in between any two of those fractions, and... then that must mean that there are not only infinite infinities, but an infinite number of those infinities. and an infinite number of those...

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