Expected Value and First Order Stochastic Dominance

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SUMMARY

The discussion centers on the relationship between expected values and first-order stochastic dominance of two random variables, X and Y. It is established that while E[X] ≥ E[Y] indicates that the expected value of X is greater than or equal to that of Y, it does not imply that X has first-order stochastic dominance over Y. An example is provided where X has states of 10 and 0, yielding E(X) = 5, while Y has states of 2 and 1, yielding E(Y) = 1.5, demonstrating that X does not dominate Y despite having a higher expected value.

PREREQUISITES
  • Understanding of expected value calculations in probability theory.
  • Knowledge of first-order stochastic dominance concepts.
  • Familiarity with random variables and their distributions.
  • Basic probability theory, including concepts of states and probabilities.
NEXT STEPS
  • Research the mathematical definitions of first-order stochastic dominance.
  • Explore examples of random variables that illustrate stochastic dominance.
  • Learn about higher-order stochastic dominance and its implications.
  • Study the applications of stochastic dominance in decision theory and economics.
USEFUL FOR

Statisticians, economists, data analysts, and anyone interested in probability theory and decision-making under uncertainty will benefit from this discussion.

odck11
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Dear All:

Given two random variables X and Y, if I have established the relationship E[X]>=E[Y], does this necessarily imply that X must have a first-order-stochastic dominance over Y?

I know that first order stochastic dominance implies that the mean value of the dominating random variable be greater than the other variable but I am trying to find out whether the reverse must hold.

Thanks in advance.
Regards.
 
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odck11 said:
Dear All:

Given two random variables X and Y, if I have established the relationship E[X]>=E[Y], does this necessarily imply that X must have a first-order-stochastic dominance over Y?

I know that first order stochastic dominance implies that the mean value of the dominating random variable be greater than the other variable but I am trying to find out whether the reverse must hold.

Thanks in advance.
Regards.
Not necessarily. Let X have two states 10 and 0, while Y has two states 2 and 1, both with equal probability. E(X) = 5, E(Y) = 1.5, but X does not dominate Y.
 
Great! Thanks a lot. That's what I guessed too but just wanted to make sure. I appreciate your fast reply.
 

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