Expected Value of X in Binomial Trials

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SUMMARY

The discussion focuses on calculating the expected value of a random variable, X, in a series of three Bernoulli trials with a success probability of p=0.4. The expected value, E[X], is determined to be 2.80 when using the binary representation of outcomes, where success (S) is represented as 1 and failure (F) as 0. When the probability of success is adjusted to P[S]=0.5, the expected value increases to 3.5. The calculation involves applying the definition of expectation, E[X] = Summation (x*P(x)), where x corresponds to the binary outcomes.

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  • Understanding of Bernoulli trials and their outcomes
  • Familiarity with the concept of expected value in probability
  • Knowledge of binary number representation
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In a series of three binomial trials with p=.4, a random variable, X, is assigned to the outcomes to form a base 2 number, with 1 associated with success(S), and 0 associated with failure(F). For example, SFS->101=5.

A) Find the expected value of X, E[X].
(Answer 2.80)

B) Find the expected value of X if P=.5
(Answer 3.5)
 
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I think you mean 3 bernoulli trials and not binomial trials. Remember bernoulli trials have just 2 outcomes (1 and 0 in your question).
Since you know the 3 digit number (from the SFS or other combinations) just use definition of Expectation.
E[X] = Summation (x*P(x))
In your case the x would be 1*2^n and 0*2^n(which is 0 so can ignore)...n is the power corresponding to the placing of the number.
As for a number at the unit's place, you would have 1*2^0.
For Bernoulli the expectation is just p and then use the definition to obtain the result.

Hope this helps.
 
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