Explain Photoelectric Effect: Potential, Formula & Voltage

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SUMMARY

The discussion centers on the photoelectric effect, specifically the concept of stopping potential and its formula, e × Vs, where V represents voltage. It is established that when a photon is absorbed, part of its energy frees an electron, with the remaining energy converted to kinetic energy. The stopping potential is defined as the voltage at which the work done by the electric field equals the kinetic energy of the freed electron. This relationship highlights that the maximum kinetic energy of the electron corresponds to the leftover energy from the photon after overcoming the work function.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Familiarity with the concept of stopping potential
  • Knowledge of kinetic energy and work-energy principles
  • Basic grasp of photon energy and its interaction with electrons
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  • Study the derivation of the photoelectric effect formula from quantum mechanics
  • Explore the work function and its significance in the photoelectric effect
  • Learn about the maximum kinetic energy of electrons in the context of photon absorption
  • Investigate advanced topics in photon-electron interactions and energy transfer mechanisms
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Students of physics, educators teaching modern physics concepts, and researchers interested in quantum mechanics and photoelectric phenomena.

Gajan1234
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Can someone explain what is stopping potenial is and can explain the formula : e × Vs. Does the v stand for voltage
 
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Gajan1234 said:
Can someone explain what is stopping potenial is and can explain the formula : e × Vs. Does the v stand for voltage
Can you show us the reading you've been doing about this please? Thanks. :smile:
 
When a photon is absorbed some of its energy is used to free the electron and what is left over is given to the freed electron as kinetic energy. The stopping potential slows the electron down and if the potential is high enough the electrons won't make it to the detector. The value of the potential at which this happens occurs when the work done by the electric field is equal to the kinetic energy. This value is eV xS, so yes V is the potential (or voltage difference).
 
Jilang said:
When a photon is absorbed some of its energy is used to free the electron and what is left over is given to the freed electron as kinetic energy.

Is that exactly true? Or is there a range of possible leftover energy transferred from the photon to the electron as kinetic, from 0 up to the entire leftover energy? I don't have the textbook with me, but in Serway's "Modern Physics", he mentions a maximum kinetic energy for the freed electron being equal to the leftover photon energy, which implies there are probably other processes which might take away said energy.
 
Jilang said:
When a photon is absorbed some of its energy is used to free the electron and what is left over is given to the freed electron as kinetic energy.
cryora said:
in Serway's "Modern Physics", he mentions a maximum kinetic energy for the freed electron being equal to the leftover photon energy, which implies there are probably other processes which might take away said energy.
In the (over)simplified treatment of the photoelectric effect that you commonly find in introductory textbooks like that, the "energy used to free the electron" is not the same for each electron. Crudely and simplistically speaking, think of it as reflecting how "deeply buried" the electron was in the material. A certain minimum energy is needed to free the electron, corresponding to a maximum kinetic energy after ejection.
 
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