Explaining Alpha Decay Energies in 232Th

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Homework Help Overview

The discussion revolves around the alpha decay of 232Th and the observed energies of the emitted alpha particles, specifically why they can have values of 4.01 MeV and 3.95 MeV. Participants are exploring the underlying reasons for these energy variations in the context of radioactive decay.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the relationship between the decay process and the different energy states of the decay products. There is an exploration of the concept of probability in decay outcomes and how different excited states of Ra228 might influence the energy of the emitted alpha particle.

Discussion Status

Some participants have provided insights regarding the decay process and the role of excited states in determining the energy of the alpha particles. However, there is still a lack of consensus on the exact mechanisms at play, and further exploration of the topic is ongoing.

Contextual Notes

Participants are considering the implications of decay probabilities and the energy states of the resulting Ra228, which may not have been fully defined in the original question. The discussion reflects an attempt to understand the complexities of radioactive decay without reaching a definitive conclusion.

jackxxny
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Homework Statement



I got ask the following question, and i don't know the answer.

Why in a rdioactive decay of 232Th by alpha emission, the alpha particle can have energy 4.01 Mev and 3.95 Mev?

Homework Equations





The Attempt at a Solution




I look up this website and i found it.

http://atom.kaeri.re.kr/cgi-bin/decay?Th-232 A

But i don't understand why.

Is because of the probility?
 
Physics news on Phys.org
Yes, there are different possible decay products with different probability weightings.
 
the part that i don't get is how Th232 -->decay--> Ra228

why does the alpha particle can have 2 different energies??
 
Judging from your picture it looks like Th will decay in the majority of cases to two different excited states of Ra (which can subsequently emit a gamma to get to the ground state of Ra). If it decays to the higher energy state of Ra then there is less energy left for the alpha.
 
well if Th232 decays by alpha emission it loses a He atom
thus Th232 = Ra228 + He4
hope this helps
 

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