Explaining Particle Existing in l=0, s=3/2

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Discussion Overview

The discussion centers around the existence of a particle characterized by quantum numbers l=0 and s=3/2, specifically exploring the implications and understanding of such a state within quantum mechanics.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant seeks clarification on how a particle can exist in the state \Psi(l=0, s=3/2).
  • Another participant expresses skepticism about the validity of quantum mechanics and questions how the spin of 3/2 is determined.
  • A repeated inquiry about the existence of the state suggests a lack of understanding or consensus on the topic.
  • A participant references the Δ particle, explaining that its 3/2 spin arises from the alignment of the spins of its constituent quarks, contrasting it with nucleons which have a different spin configuration.

Areas of Agreement / Disagreement

The discussion reflects uncertainty and differing levels of understanding regarding the existence and implications of a particle in the specified quantum state, with no clear consensus reached among participants.

Contextual Notes

Participants do not fully explore the underlying assumptions or definitions related to the quantum state in question, and there are unresolved aspects regarding the implications of the spin configuration.

quantumdude10
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Hi,
Can someone explain to me how a particle can exist in [tex]\Psi[/tex](l=0, s= 3/2).
 
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Well, QM's pretty tricky. It's hard to believe any of it actually works. Maybe you're wondering how they know the spin is 3/2.
 
quantumdude10 said:
Hi,
Can someone explain to me how a particle can exist in [tex]\Psi[/tex](l=0, s= 3/2).
Why not?
 
http://en.wikipedia.org/wiki/Delta_baryon
The 3⁄2 spin means that all the three quarks inside a Δ particle have their spin axis pointing in the same direction, unlike the nearly identical proton and neutron (called "nucleons") in which the intrinsic spin of one of the three constituent quarks is always opposite the spin of the other two. This difference in spin alignment is the only quantum number distinction between the Δ+ and Δ0 and ordinary nucleons, whose spin is 1⁄2.
 

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