Exploring Orbital Velocity: Significance and Applications

Click For Summary
SUMMARY

The discussion centers on the significance of orbital velocity in relation to the speed of light, particularly in the context of black holes and the Schwarzschild radius. The equation Vorb = √((Gm)/r) was analyzed, leading to the conclusion that the boundary where r = (Gm)/(C²) is coincidental and does not hold significance outside of Newtonian mechanics. The conversation highlights the limitations of Newtonian mechanics (NM) under extreme conditions, emphasizing the necessity of General Relativity (GR) for accurate calculations. The photon sphere, which exists outside the event horizon, is identified as a more relevant concept in this context.

PREREQUISITES
  • Understanding of orbital mechanics and gravitational forces
  • Familiarity with Newtonian mechanics (NM)
  • Basic knowledge of General Relativity (GR)
  • Mathematical proficiency in manipulating equations involving gravitational constants
NEXT STEPS
  • Study the concept of the photon sphere in relation to black holes
  • Learn about the Schwarzschild radius and its implications in astrophysics
  • Explore Post-Newtonian formalism for corrections in gravitational calculations
  • Investigate the differences between Newtonian mechanics and General Relativity under extreme conditions
USEFUL FOR

Astronomy students, astrophysicists, and anyone interested in the dynamics of black holes and the application of General Relativity in extreme gravitational fields.

travwg33
Messages
21
Reaction score
0
I am fairly new to astronomy, having just finished a course this past semester in high school, and I have a question about orbital velocity.

Now, I know that the event horizon is the boundary at which the escape velocity is equal to the speed of light, but is there any significance to the boundary at which the orbital velocity is equal to the speed of light?

I quickly messed around with the math to see where such a boundary would lie and determined this:
Vorb = √((Gm)/r)

substitute Vorb for C

C = √((Gm)/r)
r = (Gm)/(C2)

This is obviously very similar to determining the Schwarzschild radius and this boudary would actually be inside the event horizon, light orbiting the singularity, but never moving out past the radius once in orbit.

I looked online to see if such a boundary was important or existed and I think I found something similar the photon sphere, but the equation is different and this sphere is outside the event horizon.

Does the boundary where r = (Gm)/(C2) mean anything?
 
Astronomy news on Phys.org
Does the boundary where r = (Gm)/(C2) mean anything?
No. It's a coincidence that a Newtonian calculation gives the correct result for the Schwarzschild radius (he's not a child, btw). You can't expect that it works for other qunatities.
If you do the calculations in GR, you get the photon sphere result. For illustration, think that the centrifugal force reverses direction near the horizon, where relativity becomes important. Thus, it's even harder to orbit than to escape.
 
Ah ok that makes sense. Thanks for clarifying that up :)
 
Just thinking, I do not know too much about Newtonian mechanics or GR, but does this mean that NM breaks down under extreme conditions?
 
Exactly. It works if you have small velocities and weak gravity. It's like a first order approximation to the exact GR laws.
You can make it work more exactly or for more extreme circumstances if you include some corrections, like a second order approximation to GR. That's called the Post-Newtonian formalism.
Under the most extreme conditions, you use full GR.
 
https://en.wikipedia.org/wiki/MoM-z14 Any photon with energy above 24.6 eV is going to ionize any atom. K, L X-rays would certainly ionize atoms. https://www.scientificamerican.com/article/whats-the-most-distant-galaxy/ The James Webb Space Telescope has found the most distant galaxy ever seen, at the dawn of the cosmos. Again. https://www.skyatnightmagazine.com/news/webb-mom-z14 A Cosmic Miracle: A Remarkably Luminous Galaxy at zspec = 14.44 Confirmed with JWST...

Similar threads

Replies
2
Views
3K
Replies
2
Views
2K
Replies
9
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
10
Views
9K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
15
Views
3K
  • · Replies 20 ·
Replies
20
Views
2K