A 3.55 kg object sliding on a frictionless surface breaks into two masses that are both equal to half of the original mass. The velocities of the masses are 3.26 m/s due north and 4.58 m/s, 25.4° north of east. Determine the original speed of the 3.55 kg mass.
p = mv
Ek = 1/2 mv^2 But this isn't an elastic collision, so the conservation of energy wouldn't work
The Attempt at a Solution
Momentum is conserved.
(I'm assuming the mass is moving in a horizontal direction)
m1x v1x = m2x v2x cos(theta)
(3.55)(v1x) = (3.55/2)(4.58)(cos 25.4)
2(v1x) = (4.58)(cos25.4)
v1x = 2.07 m/s
Erm... I resolved it in terms of the x direction so I'm not sure why it isn't working...