Exterior derivatives on fibre bundles

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SUMMARY

This discussion focuses on the application of exterior derivatives on principal bundles, specifically regarding the Ehresmann connection represented by a Lie-algebra valued one-form, omega. The user inquires about the identification of the exterior derivative d on the principal bundle P, referencing Nakahara's text. The resolution involves recognizing the relationship between the fundamental vector field A* and the differential of the gauge potential, leading to the conclusion that A(g) = dg(A).

PREREQUISITES
  • Understanding of principal bundles and Ehresmann connections
  • Familiarity with Lie algebra and its applications in gauge theory
  • Knowledge of differential geometry, particularly exterior derivatives
  • Proficiency in the notation and concepts presented in Nakahara's "Geometry, Topology and Physics"
NEXT STEPS
  • Study the properties of Ehresmann connections in principal bundles
  • Explore the role of Lie algebra in gauge theories
  • Learn about the application of exterior derivatives in differential geometry
  • Review Nakahara's chapter 10 for deeper insights into gauge potentials
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This discussion is beneficial for mathematicians, theoretical physicists, and graduate students specializing in differential geometry, gauge theory, and the mathematical foundations of physics.

haushofer
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Hi, I have a small question about exterior derivatives d on defined on principal bundles P.

We have the Ehresmann connection on a principal bundle P, represented by a Lie-algebra valued one-form omega. We can use the section sigma to pull this one-form back to our basemanifold, where the interpretation of a gaugepotential comes in.

Now one postulates this omega on P and checks if it fullfills the 2 axioms of this connection one-form. Now they (Nakahara chapter 10 ) use the following identification, which I don't see:

<br /> d_{P} g_{i} (A^{*} ) = \frac{dg(ue^{tA})}{dt} \ |_{t=0}<br />

Here g_{i} is the canonical local trivialization,

<br /> \phi_{i}^{-1}(p,g_{i}) = (p,g) \, \ \ \ u = \sigma_{i}(p) g_{i}<br />

, A is an element of the Lie-algebra and A^{*} is the fundamental vector field lying in the vertical subspace:

<br /> A^{*}f(u) = \frac{d}{dt}f(ue^{tA}) \ |_{t=0}<br />

Anyone an idea?
 
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Okiedokie, solved the problem. :')

Just an application of X(f) = df(X), so A(g) = dg(A).
 

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