We know that in the continous math, e is special number because if f(x) = e^x, so f'(x) = f(x). But in discrete math, what's the constante base that satisfies this condition? Is not the 2? I. e. f(n) = 2^n ?(adsbygoogle = window.adsbygoogle || []).push({});

Thanks,

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# I F'(n) = f(n) in discrete calculus

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