Factor 2e^3x - 5xe^3x and 4lnx - 3ylnx

[name_ask17]

Homework Statement

Okay, I think these are simple, but just so I know that I am on the right track, can you double check my work? My questions and answers are in bold.

Factor these completely:

1. 2e^3x - 5xe^3x

2. 4lnx -3ylnx

3. The Attempt at a Solution

1. I took out the e^3x to make the factored problem e^3x(2-5x)Did I do that right, because I get confused when dealing with the exponents. If there is more to it, can you explain please? Thanks in advance.

2. I just took out the lnx to make it lnx(4-3y) . Is this correct?

 

[LCKurtz]

Homework Statement

Okay, I think these are simple, but just so I know that I am on the right track, can you double check my work? My questions and answers are in bold.

Factor these completely:

1. 2e^3x - 5xe^3x

2. 4lnx -3ylnx

3. The Attempt at a Solution

1. I took out the e^3x to make the factored problem e^3x(2-5x)Did I do that right, because I get confused when dealing with the exponents. If there is more to it, can you explain please? Thanks in advance.

2. I just took out the lnx to make it lnx(4-3y) . Is this correct?

They are both correct but you need parentheses. For example e^(3x). Also, while not incorrect, it is better to write the last one (4-3y)ln(x) to remove any possible misunderstanding about what is inside the ln function.

 

[name_ask17]

Thanks! Just wanted to make sure they were correct because it seemed too simple. Guess I'm used to overthinking things. lol.