Factor Equation: (1-v^2/c^2)^3/sqr((1-v^2/c^2)^2)

[whozum]

I think we are both on the same page here. Yes, my equation does not describe anything physical. But, if you look at a graph of time dilation, you can almost predict or assume (logical) that if v > c then -t. But I have not taken any courses on relativity (although I want to), and all of my studies are straight from the NET. And the NET has some very innacurate and misleading statements therein.

You keep doing exactly what we tell you not to do. You are graphing a function that has a physical meaning, and then changing the function and trying to interpret the physical meaning of the new function. Theres a reason the absolute value sign isn't in there.

IF
f(x) = \sqrt{|1-\frac{x^2}{k}|} AND x^2 > k

THEN f(x) would be negative. This is 100% correct. Thsi is as far as you can take your problem without starting to **** with relativity theories.

 

[eNathan]

You keep doing exactly what we tell you not to do. You are graphing a function that has a physical meaning, and then changing the function and trying to interpret the physical meaning of the new function. Theres a reason the absolute value sign isn't in there.

IF
f(x) = \sqrt{|1-\frac{x^2}{k}|} AND x^2 > k

THEN f(x) would be negative. This is 100% correct. Thsi is as far as you can take your problem without starting to **** with relativity theories.

I see what you are saying. I am fully awear that I have changed the original meaning of the Lorenze Transformation, and therefore we cannot accept the new result as a physical meaning. I am just saying "it would be kewl if v > c was posible, and if it was it would resutl in -t. And if this was so perhaps this equation could predict it". I am in not way accepting my equation as something that actually exists. I just like playing with mathematics.

What is the meaning of f(x) = \sqrt{|1-\frac{x^2}{k}|} AND x^2 > k by the way? It looks like a 'take off' of the LT factor.

 

[whozum]

"it would be kewl if v > c was posible, and if it was it would resutl in -t. And if this was so perhaps this equation could predict it"

I agree.

What is the meaning of f(x) = \sqrt{|1-\frac{x^2}{k}|}
AND x^2 > k
by the way? It looks like a 'take off' of the LT factor.

It is the LT factor just as a regular function f(x).k = c^2, f(x) = \gamma, x = v

 

[dextercioby]

1.It's not Lorenze,it's HENDRIK ANTOON LORENTZ.
2

.\gamma=:\frac{1}{\sqrt{1-\frac{v^{2}}{c^{2}}}}​

Daniel.
​

 

[whozum]

He was spelling things wrong left and right, I'm not a dictionary, I don't care.

 

[dextercioby]

U had a problem with the "gamma factor" yourself...

Daniel.

 

[whozum]

I copied the one he pasted thinking it was the original one, didnt see the absolute values. I am only human dex. Sure its inverted too.

We can't all fuse into a physics gurus.

 

[abia ubong]

hey zurtex i need more xplanations

 

[Zurtex]

hey zurtex i need more xplanations

I've given up on eNathan threads, if you look back I've already explained it all and where the confusion came from. What exactly if your issue? Perhaps you could start another thread with a problem you have.